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Q: What is the solution set of -9x 27?

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9x+27 = -81 9x = -81-27 9x = -108 x = -12

10x = 9x -25 10x -9x = -25 x = -25

-9x + 4 = -50 -9x = -50 - 4 -9x = -54 -x = -6 x = 6.

(-9x^2/√x) + 4= [-9x^2/x^(1/2)] + 4= (-9x^2)[x^(-1/2)] + 4= -9x^[2 + (-1/2)] + 4= -9x^(2 - 1/2) + 4= -9x^(3/2) + 4= -9√x^3 + 4= -9√[(x^2)(x)] + 4= -9x√x + 4Or,(-9x^2/√x) + 4= [(-9x^2)(√x)/(√x)(√x)] + 4= [(-9x^2)(√x)/√x^2] + 4= [-9(x)(x)(√x)/x] + 4 simplify x= -9x√x + 4

-9x+6y = 54 6y = 9x+54 y = 1.5x+9 slope = 1.5

Related questions

9x + 2x + 26 is an expression, not an equation (or inequality). It therefore cannot have a solution so that its solution set is the null set. There is nothing in the solution set - no integers, rationals, irrationals: nothing!

9x+27 = -81 9x = -81-27 9x = -108 x = -12

-3x = 9x = 9/(-3)x = -3

If you mean: 7x-53 = 9x Then the solution is: x = -26.5

273x+1 = 9 33(3x+1) = 32 9x+3 = 2 9x = 2-3 9x = -1 x = -1/9 Check: 27(3*-1/9)+1 = 9

10.8

9x+6=51 9x = 45 x= 5 9x-6=51 9x = 57 x= 6.33

9*27 = 243

9x-27=7x-1 9x-7x= -1+27 26=2x x=26 / 2 therefore x=13

9x + 2 = x - 5Subtract 'x' from each side of the equation:8x + 2 = -5Subtract 2 from each side:8x = -7Divide each side by 8 :x = -7/8The solution set is { -7/8 } .

12x + 6=9x + 27 12x-9x + 6=9x - 9x + 27 subtract 9x from both sides. 3x + 6 = 27 simplify 3x + 6 - 6=27 - 6 subtract 6 from both sides. 3x=21 simplify 3x/3=21/3 divide both sides by 3 x=7 simplify 12(7) + 6=>84+6=>90 9(7) + 27=>63+27=>90 It checks out!

Divide both sides by 9: 9x > 27 → x > 3

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