-9x = 27
x = -3
The solution set contains only one value for x, -3, which is just a point on the number line 3 units to the left of zero.
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9x+27 = -81 9x = -81-27 9x = -108 x = -12
10x = 9x -25 10x -9x = -25 x = -25
-9x + 4 = -50 -9x = -50 - 4 -9x = -54 -x = -6 x = 6.
3x2 = 27Divide each side by 3:x2 = 9Take the square root of each side:x = + 9x = - 9
(-9x^2/√x) + 4= [-9x^2/x^(1/2)] + 4= (-9x^2)[x^(-1/2)] + 4= -9x^[2 + (-1/2)] + 4= -9x^(2 - 1/2) + 4= -9x^(3/2) + 4= -9√x^3 + 4= -9√[(x^2)(x)] + 4= -9x√x + 4Or,(-9x^2/√x) + 4= [(-9x^2)(√x)/(√x)(√x)] + 4= [(-9x^2)(√x)/√x^2] + 4= [-9(x)(x)(√x)/x] + 4 simplify x= -9x√x + 4