0
x=2 1/7
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
Where are the points of intersection on the x axis when y equals 8x squared -26x plus 15?
(3/4, 0) and (5/2, 0) Solved with the help of the quadratic equation formula.
What is x squared minus 8x plus 8y plus 32 equals 0 in standard parabola form?
7
X2 plus 8x 12 equals 0 in quadratic formula?
x2+8x+12 = 0 When factorized: (x+6)(x+2) = 0 Therefore: x = -6 or x = -2
Explain how to solve x2 plus 8x -2 equals 0 by completing a square?
x2 + 8x - 2 = 0 => x2 + 8x = 2 => x2 + 8x + 16 = 2 + 16 = 18 => (x + 4)2 = 18 => x + 4 = +or- sqrt(18) = +or- 3*sqrt(2) so x = -4 +or- 3*sqrt(2)
What is the real solution for the equation x2-8x-4 equals 0?
I'll show work. X2-8x-4=0. X2-8x=4. X-8x=2. -7x=2. X=-(2/7).
Factor x squared - 8x plus 15 equals 0?
(x-3)(x-5) = 0
What is the x value of -8x plus 8x plus 4 equals -24?
- 8x + 8x = 0 so question is meaningless.
X2-8x plus 32 equals 0?
no
Put the equation in the form ax2 plus bx plus c equals 0 x2-3 equals 3x2 plus 8x?
2x^2 + 8x + 3 = 0
Factor X2 plus 8x equals -15?
x2 + 8x = -15 x2 + 8x + 15 = 0 since 15 = 5 x 3 and 5 + 3 = 8, then (x + 5)(x + 3) = 0 x + 5 = 0 or x + 3 = 0 x = -5 or x = -3
X2-8x plus 15 equals 0?
x2 - 8x + 15 = 0 can be factored as (x - 3)(x - 5) = 0 : This holds true when one or both of the terms in brackets equals zero. When x - 3 = 0 then x = 3 When x - 5 = 0 then x = 5.
Y equals x2 plus 8x plus 15?
y = x2 + 8x + 15 = (x + 3)(x + 5). When y = 0, one or other of the two factors must equal zero; that is, x = -3 or -5, when y = 0.
How do you factorise x3 plus 2x2-8x plus 5 equals 0?
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
8x plus 32 plus 24 equals 0?
8x + 32 + 24 = 0 So 8x + 56 = 0 Subtract 56 from both sides: 8x = -56 Divide both sides by 8: x = -7
What is the answer to 8x plus 8 equals 9x-18 plus 9?
8x+9=9x-18+9 = 8x+9=9x-9 = 1x=0 (:
-8x plus 5y equals 10?
x=0 y=2
What is the square root of x square plus 8x plus 15 equals 0?
x2 + 8x + 5 = 0 is an expression, not a value, and thus does not actually have a square root. If you are looking to solve for x, then you can say: x2 + 8x + 5 = 0 ∴ x2 + 8x + 16 = 11 ∴ (x + 4)2 = 11 ∴ x + 4 = ±√11 ∴ x = 4 ±√11
