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If the discriminant is positive the equation has solution s?
two real
What are the compex roots in mathematics?
The complex roots of an equation is any solution to that equation which cannot be expressed in terms of real numbers. For example, the equation 0 = x² + 5 does not have any solution in real numbers. But in complex numbers, it has solutions.
How many real solutions does a cubic equation have?
A cubic has from 1 to 3 real solutions. The fact that every cubic equation with real coefficients has at least 1 real solution comes from the intermediate value theorem. The discriminant of the equation tells you how many roots there are.
What is the discriminant and how is it used to solve equations using the quadratic formula?
It is not to solve so much as to see the number of solutions and whether there is a real solution to the equation. b2 - 4(a)(c) A positive answer = two real solutions. A negative answer = no real solution ( complex solution i ) If zero as the answer there is one real solution.
Find the domain and range of the equation 3x - 2y equals 6?
domain is set of real numbers range is set of real numbers
If the discriminant of a quadratic equation equals zero what is true of the equation?
It has one real solution.
What is 8 equals 8v-4v8?
8 = 8v - 4v8 This equation does not have any real solution.
Solve for x 3 - x 7?
-4
What is the value of x in the equation x squared minus x plus 7 equals 3?
The equation does not have a real number solution. Using the quadratic formula will give it's conjugate pair complex solution.
How many real number solutions does the equation have y equals 3x2 plus 18x plus 27?
It has one double solution.
If the discriminant of an equation is positive.What is true of the equation?
The equation has two real solutions.
What is solution of x2 equals -1 in real number?
3
What is the solution to x2 plus 7x plus 14 equals 0?
You should be able to look at this equation, or use the discriminant and know that there are no real roots.
How many real and imaginary solutions of the equation X13 equals 1?
There is one and only one real solution, and no imaginary solutions, of the equation x13 = 1. The solution is x = 1. If x = -1 then x13 = -1, so that does not work. If x = i, then x13 = -i, so that does not work. If x = -i, then x13 = -i, so that does not work.
Is it possible for a quadratic equation to have no real solution give examle ansd explain?
Is it possible for a quadratic equation to have no real solution? please give an example and explain. Thank you
How many and what type of solutions does the quadratic function x2 -10x plus 25 equals 0 have?
You are supposed to calculate the so-called discriminant, b2 - 4ac. If the result is positive, the equation has two real solutions; if it is zero, one real solution; if it is negative, no real solution (and two complex solutions). For this particular equation, a = 1, b = -10, and c = 25.
2y equals -4x - 5?
This is an equation of a straight line. A solution for two unknowns requires two (independent) equations; there is only one here. Every point that is on that line is a solution to the equation. So you can let x be any real number and find a corresponding y. This ordered pair (x,y) will be a solution to the equation as well as a point on the graph of the line.
