take 15ml od dettol solution and add into 285 ml of water . then you wll get 5% of dettol solution
To prepare a 5% potassium iodide solution, weigh 5 grams of potassium iodide and dissolve it in 100 mL of water. Stir until the potassium iodide is completely dissolved to achieve a 5% solution.
Check what it is dissolved in first and use the same solvent for dilution. If you want to make a litre of 10% for instance, You want to dilute it 10 in 26 parts or 5 in 13. So 1 litre /13*5 is 384.6ml of 26% ammonia, and dilute to 1 litre with solvent
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
A 5% dextrose solution is composed of 5 grams of dextrose (glucose) per 100 milliliters of solution. It is commonly used as a source of energy and as a mild hypertonic solution in medical settings.
To prepare a 5% potassium iodide solution, weigh 5 grams of potassium iodide and dissolve it in 100 mL of water. Stir until the potassium iodide is completely dissolved to achieve a 5% solution.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
To prepare 100 ml of a 5% dextrose solution from a 50% dextrose solution, you would use the formula: C1V1 = C2V2. You will need 10 ml of the 50% solution (C1) and dilute it with 90 ml of water (V1) to obtain the desired 100 ml of 5% dextrose solution.
To prepare 1 liter of a 5% alcohol-water solution, you would mix 50 mL of alcohol with 950 mL of water. This ratio would give you a total volume of 1 liter with 5% of it being alcohol.
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.
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Take 5% of 350g = 17.5 g sugarand add 350g -17.5g = 332.5 g solvent (water, most likely, this is 333 mL)
get 5%
Check what it is dissolved in first and use the same solvent for dilution. If you want to make a litre of 10% for instance, You want to dilute it 10 in 26 parts or 5 in 13. So 1 litre /13*5 is 384.6ml of 26% ammonia, and dilute to 1 litre with solvent
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
You dillute it with some more of the same solvent used for the 6 percent solution - pressumably water.