first calculate
vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
23.75 mg of Dextrose is added by intravenous injection of 475 ml of this solution .. wrong!5% WV means 5 grams/100ml ; therefore 23.75 grams/475ml; since there's 1000mg/gramthe number of mg dextrose added by IV injection of 475ml = 23750mg !
To find the number of grams of dextrose in a 1L solution with 5.5% concentration, you can use the formula: mass = volume x concentration. So, for this case, it would be 1L x 5.5% = 55g of dextrose in a 1L solution.
Normal Saline Solution in 5% Dextrose or D5NSS is a hypertonic solution. It can be used for the temporary treatment of shock if plasma expanders are not available. However, do not administer this IV for clients with cardiac or renal conditions.
To prepare 1 liter of a 5% alcohol-water solution, you would mix 50 mL of alcohol with 950 mL of water. This ratio would give you a total volume of 1 liter with 5% of it being alcohol.
Add 10 g to a volumetric flask and make up to the 1 liter mark.
A 10 percent solution of dextrose means that there are 10 grams of dextrose per 100 milliliters of solution. Therefore, in 1000 milliliters (which is 10 times 100 ml), there would be 10 grams x 10 = 100 grams of dextrose in a 1000 ml solution.
In a 70% dextrose solution, 70% of the total weight is dextrose. To calculate the grams of dextrose in 400ml of this solution, you would multiply 400ml by 70% (or 0.70) to find the amount of dextrose present.
pharmacist
23.75 mg of Dextrose is added by intravenous injection of 475 ml of this solution .. wrong!5% WV means 5 grams/100ml ; therefore 23.75 grams/475ml; since there's 1000mg/gramthe number of mg dextrose added by IV injection of 475ml = 23750mg !
To find the number of grams of dextrose in a 1L solution with 5.5% concentration, you can use the formula: mass = volume x concentration. So, for this case, it would be 1L x 5.5% = 55g of dextrose in a 1L solution.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
Dextrose is a solid so it doesn't really have a pH until it is in solution. Once it is in solution, it would depend on what the solvent was and the concentration of the dextrose. So it could range greatly, but most are kept around 6.4.
To prepare a 40.0% lithium nitrate solution, 60mL of the solution would be solvent (water) and 90mL would be solute (lithium nitrate). Therefore, you would need 90mL of lithium nitrate to prepare 150mL of the 40.0% solution.
Normal Saline Solution in 5% Dextrose or D5NSS is a hypertonic solution. It can be used for the temporary treatment of shock if plasma expanders are not available. However, do not administer this IV for clients with cardiac or renal conditions.
To prepare 1 liter of a 5% alcohol-water solution, you would mix 50 mL of alcohol with 950 mL of water. This ratio would give you a total volume of 1 liter with 5% of it being alcohol.
Add 10 g to a volumetric flask and make up to the 1 liter mark.