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1/103 = 0.001 M HCl, so.....

Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )

0.001 M HCl = X moles HCl/0.025 Liters

= 2.5 X 10 - 5 moles HCl

========================now, balanced eqiation

NaOH + HCl --> NaCl + H2O ( all one to one )( now drive reaction towards mass NaOH )

2.5 X 10 - 5 moles HCl (1 moles NaOH/1 mole HCl)(39.998 grams/1 mole NaOH)

= 10 -4 grams caustic soda needed

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