One step at a time.
1/103 = 0.001 M HCl, so.....
Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )
0.001 M HCl = X moles HCl/0.025 Liters
= 2.5 X 10 - 5 moles HCl
========================now, balanced eqiation
NaOH + HCl --> NaCl + H2O ( all one to one )( now drive reaction towards mass NaOH )
2.5 X 10 - 5 moles HCl (1 moles NaOH/1 mole HCl)(39.998 grams/1 mole NaOH)
= 10 -4 grams caustic soda needed
==========================
To neutralize the 25ml of 3M acid, you would need to find the number of moles of acid present, which is 25ml * 3M = 75 millimoles. Then, you would need the same number of millimoles of the 8M base to neutralize it, so you would need 75 millimoles / 8M = 9.38ml of the 8M base.
According do their website, 5g of sucrose (table sugar) per 25ml.
2 litres is equivalent to 2000 ml. Thus it is 80 x 25 ml.
To make 1 liter of 0.1 M NaCl solution, you will need 25 ml of the 4 M NaCl stock solution and 975 ml of water. This will give you the desired concentration of 0.1 M NaCl in a total volume of 1 liter.
The normality of the unknown acid solution is 0.625 N. This can be calculated by using the equation: Normality of acid x volume of acid = Normality of base x volume of base. Given that 25mL of 0.5 N NaOH neutralizes 30mL of the acid, you can set up the equation and solve for the normality of the acid.
To neutralize the 25ml of 3M acid, you would need to find the number of moles of acid present, which is 25ml * 3M = 75 millimoles. Then, you would need the same number of millimoles of the 8M base to neutralize it, so you would need 75 millimoles / 8M = 9.38ml of the 8M base.
Graduated
add 25ml more of solution x * 20 = 100 * 25 x = 25
EDTA can be standardized by using a number or reagents, although this is often unnecessary, as it can be purchased in pure form. Standardizing against magnesium is done by dissolving 0.24g magnesium in 25mL 1M Hydrochloric solution, diluting the mixture out to 1 liter, taking 25mL of that solution and adding 75mL of water, 2mL of pH 10 ammonia buffer and a pinch of indicator ground with salt. Then titrate the EDTA solution that is being standardized until the incicator solution turns blue. The purity of the EDTA solution will then be indicated by the amount of solution used, by using a table or calculation software.
1 ml = 1g of water so 25ml would weight 25 grams
According do their website, 5g of sucrose (table sugar) per 25ml.
A 1.5-liter bottle contains 1500 milliliters. To find out how many 25ml drinks can be poured from this bottle, divide 1500ml by 25ml. This calculation yields 60 drinks. Therefore, you can get 60 servings of 25ml from a 1.5-liter bottle of spirits.
25000
2
Yes, 5ml is smaller than 25ml. 5cc < 25cc's. (1 ml = 1 cc)
2 litres is equivalent to 2000 ml. Thus it is 80 x 25 ml.
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