4.1858 joules of energy will raise the temperature of 1 g of water by 1oC.
Thus, 4.1858 * 955 * 80 = 319795.12 joules of energy is required to raise the temperature of 955 g of water by 1oC.
The necessary energy is 6 kcal.
false its 1 degrees Celsius
The necessary heat is 1,45 kcal.
Using the formula Q=mcΔT, the amount of heat energy required is (82g)(4.18J g-1 K-1)(42K) = 14400J.
The amount of energy to boil water depends on two things: the amount of water and the temperature of the water when you start.The more water water, the more energy it takes. The colder the water, the more energy it takes.Let say the water is at room temperature, or 20 °C. First, the water must be heated to 100 °C, which takes energy. The amount of energy is given by the specific heat of water, which is 4.186 Joule/gram °C. That means that requires 4.186 Joules of energy to heat 1 kilogram of water by 1 °C. So if you have 1 kilo grams of water at 20 °C, you have to add this much energy:= (4.18Joule/gram °C) (100g) (100 °C - 20 °C)= 334400 joules/°COf course, if you had more or less water, or it was colder or warmer, you would adjust this equation accordingly..
the heat is a form of energy...and heat is stored is the water...so heat energy become potential energy because heat is stored in water
19.7 kJ
I believe it is Calorie.
false its 1 degrees Celsius
Heat
The energy required to heat something is the product of the object's mass, its heat capacity, and how many degrees you want to raise the temperature. For example, if you fill your kettle with water, it takes longer to boil than if you only fill it partially.
No heat (energy) is required to freeze water (from liquid to solid). Freezing RELEASES energy (heat), as it is an exothermic event. If you want to know how much energy is release, you need to know the heat of fusion for water, and then multiply that by the mass of water being frozen.
A watt is a unit of power: what is required is probably the amount of energy - which is measured in joules.
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
Heat required to have such a change of state is called latent heat. If L J/kg is the latent heat per kg of water then for M kg of water we need M* L joule of heat energy
Any external heat source can provide the required energy.
314j
The necessary heat is 1,45 kcal.