0
What else can I help you with?
How much heat energy will be required to raise the temperature of 15 grams of water 25 degrees c?
The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate the heat energy as follows: Q = 15g * 4.18 J/g°C * 25°C = 1567.5 J. Therefore, 1567.5 Joules of heat energy will be required to raise the temperature of 15 grams of water by 25 degrees Celsius.
True or false a calorie is the amount of heat energy required to raise the temperature of 1 g of water 2 degrees C?
True. A calorie is defined as the amount of heat energy needed to raise the temperature of 1 gram of water by 1 degree Celsius.
What energy is required to melt 18.2g of water?
The energy required to melt a substance is known as its heat of fusion. For water, the heat of fusion is 334 J/g. Therefore, to melt 18.2g of water, the energy required would be 18.2g x 334 J/g = 6078.8 J.
A pot of water containing 10.2kg of water st 7 degrees celsius is heated until 3.1kg of water has boiled away How much heat energy was required?
This can be solved in two steps. First, you need to heat the water to the boiling point. If no additional data is given, you can usually assume that the boiling point is ca. 100 °C. Multiply the mass of the water times the temperature difference times the specific heat for water. Please note that for this part, ALL of the water must be heated up. Then, the water must be evaporated; in this case, only the part that boils away. Here, you must multiply the mass (3.1 kg) times the latent heat of water.
What is the thermal energy needed to completely vaporize 18.02g of water at 100 degrees?
To calculate the amount of energy require to vaporise water at 100C You need to first find the Latent heat of Vaporisation which for water is 2260kJ/kg So to find the amount of energy required you merely multiply the mass of the water in kg by 2260. Density of water is more or less 1kg per litre at room temperature however at 100C it could be less
How much energy is needed to change 125g of ice at -32.9 degrees to water at 75 degrees?
To calculate the energy needed to change ice at -32.9 degrees to water at 75 degrees, you need to consider the energy required for three steps: Heating ice from -32.9 degrees to 0 degrees (specific heat capacity of ice) Melting ice at 0 degrees into water at 0 degrees (latent heat of fusion of ice) Heating water from 0 degrees to 75 degrees (specific heat capacity of water) Once you have the energy needed for each step, you can add them together to find the total energy required.
What energy unit is defined as the heat required to raise one kilogram of water by one degrees celsius?
I believe it is Calorie.
How much joules does it take to heat water to 100 degrees?
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
How long would it take to heat 200 gallons of water 180 degrees if the water was 50 degrees and you only had 600 Btu water heater?
To calculate the time it would take to heat 200 gallons of water by 180 degrees using a 600 Btu water heater, you would first determine the total heat required: Calculate the heat energy required: Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat of water, and ΔT is the temperature change. Then, calculate the time required to heat the water using the formula: Time = Q / power of the heater. These calculations will give you an estimate of the time needed to heat the water based on the specific heat capacity of water and the power of the heater.
How much energy is required to raise 21kg of water by 2 degrees Celsius?
The specific heat capacity of water is 4.18 J/g°C. To calculate the energy required to raise 21 kg of water by 2 degrees Celsius, use the formula: Energy = mass x specific heat capacity x temperature change. Plugging in the values, the energy required is 21,084 Joules.
What is 1 joule of heat?
One joule of heat is equivalent to the amount of energy required to raise the temperature of 1 gram of water by 0.24 degrees Celsius. It is a small unit of energy commonly used in the field of thermodynamics to quantify heat energy.
How much heat energy is needed to convert 50 kg of water at 8 degrees Celsius to steam at 100 degrees Celsius?
The process involves increasing the temperature of water from 8°C to 100°C and then changing its phase to steam at 100°C. The total heat energy required can be calculated using the specific heat capacity of water and the heat of vaporization. The formula Q = mcΔT can be used to find the heat energy needed, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.
How many joules of heat energy must be supplied to 21 g of water to raise the temperature of the water from 24 to 95 degrees Celsius?
The specific heat capacity of water is 4.18 J/g°C. To find the heat energy needed to raise the temperature, you can use the formula: Q = m * c * ΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. Plugging in the values, you can calculate the heat energy required.
How much heat energy will be required to raise the temperature of 15 grams of water 25 degrees c?
The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate the heat energy as follows: Q = 15g * 4.18 J/g°C * 25°C = 1567.5 J. Therefore, 1567.5 Joules of heat energy will be required to raise the temperature of 15 grams of water by 25 degrees Celsius.
True or false a calorie is the amount of heat energy required to raise the temperature of 1 g of water 2 degrees C?
True. A calorie is defined as the amount of heat energy needed to raise the temperature of 1 gram of water by 1 degree Celsius.
How many kilo joules of energy are released when 1.60 kg of water cools from 80.0 degrees Celsius to 60.0 degrees Celsius?
The specific heat capacity of water is 4.18 J/g°C. First, calculate the heat energy required to cool the water from 80.0°C to 60.0°C using the formula: q = mcΔT, where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change. Then, convert the heat energy from joules to kilojoules.
How does the mass of an object affect the energy required to heat it Also give example.?
The energy required to heat something is the product of the object's mass, its heat capacity, and how many degrees you want to raise the temperature. For example, if you fill your kettle with water, it takes longer to boil than if you only fill it partially.
