মোবাইল নাম্বার 01999103997
To cool 30000 gallons of water by 5-8 degrees, you would need approximately 215-320 pounds of dry ice. Each pound of dry ice can cool about 10 gallons of water by 1 degree. So, for a 5-8 degree temperature drop in 30000 gallons of water, you would need to use 215-320 pounds of dry ice.
There are approximately 224 gallons of water in 1 ton. Therefore, 150 tons of water would be around 33,600 gallons.
230 pounds of water would be equal to approximately 27.6 gallons.
800 pounds of water would be 95.8 US gallons.
That depends on the type material you are referring to. Also, these are two different types of measurements. Gallons is a measure of volume but the other is weight or mass. Please edit your question to include more context or details.
The amount of propane needed to heat a 50 gallon water heater from 75 degrees to 105 degrees would depend on factors such as the efficiency of the water heater, the starting temperature of the water, and the ambient temperature. It is difficult to provide an exact amount without this information.
how hot is the boiling water? That makes a big difference? (is that a homework question?) I'm just trying to apply logic here, bear in mind there may be some special properties that you may have to account for like the glass/plexiglas that the water is in will have to have its temp raised also. So here goes... Raising 500 gallons of water 20 degrees would seem to require a combined value of 10,000 degrees (500 gallons times 20 degrees). So first you need to know the temperature difference between the existing water and boiling. Then devide the resulting difference into the 10,000 degrees for your simplistic answer. However, it is a bit more complicated if the tank is full at 500 gallons because you have no room to add the boiling water. That is, it would roughly take 62 gallons of boiling water to raise 500 gallons of 50 degree water to 70 degrees and the tankwouyld obviously overflow. So if it was already full you would have had to remove 62 gallons first leaving 438 gallons and consequently reducing your degree needs to 8760 degrees which means if you add the 62 gallons of boiling water you would have ended up with 72.7 degree water. So, I'd reduce the capacity to 445 gallons and add 55 gallons of boiling water and you should be pretty close.
To cool 30000 gallons of water by 5-8 degrees, you would need approximately 215-320 pounds of dry ice. Each pound of dry ice can cool about 10 gallons of water by 1 degree. So, for a 5-8 degree temperature drop in 30000 gallons of water, you would need to use 215-320 pounds of dry ice.
If you are referring to imperial gallons, about 45 inches tall.
Suppose G gallons are used. Before mixing, you have 5*65 + G*120 = 325 + 120G gallon-degrees. After mixing, you have (5+G)*70 gallon-degrees So 325 + 120G = (5+G)*70 = 350 + 70G So 50G = 25 G = 0.5 gallons.
The number of pounds in a gallon of water changes with temperature. At 100 degrees Celsius, there is about 8 lbs. per gallon of water. So with one thousand lbs. of steam, we would have around 125 gallons of water.
It is a water heater, not a hot water heater. There would be little point in using a hot water heater. I assume that is your point.
200 gallons of water would weigh approximately 1,667 pounds.
There are approximately 224 gallons of water in 1 ton. Therefore, 150 tons of water would be around 33,600 gallons.
230 pounds of water would be equal to approximately 27.6 gallons.
800 pounds of water would be 95.8 US gallons.
Of water no. Water would be about 32 pounds in 4 gallons.