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The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.

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First, calculate the volume percentages of ethanol and water in the solution. Since we know the density of both solvents, convert the percentages to mass (using density and volume). Then calculate the mole fraction of ethanol by dividing the moles of ethanol by the total moles of all components in the solution. Finally, calculate molality using the moles of solute (ethanol) and the mass of the solvent (water).

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Q: What are the mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume-The density of water is 1.00g per mL and that of ethanol is 0.789 grams per mL?
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