The shortest path with at most k edges between two points in a graph is known as the k-shortest path. It is the path that has the fewest number of edges while still connecting the two points.
Some example problems that demonstrate the application of calculus of variations include finding the shortest path between two points, minimizing the surface area of a container for a given volume, and maximizing the efficiency of a system by optimizing a function.
No, not every possible minimal spanning tree of a given graph has an identical number of edges.
The longest simple path in a graph is the path that does not repeat any vertices and has the most number of edges between two distinct vertices.
The Knight's Shortest Path Algorithm is used in computer science to find the shortest path that a knight piece can take on a chessboard to reach a specific square from a given starting position.
The k center problem is a mathematical optimization problem where the goal is to select k centers from a set of points in a way that minimizes the maximum distance between each point and its nearest center. This problem is important in various fields such as facility location and network design, where efficient clustering of points is needed.
Without wishing to overcomplicate matters, one could simply define a straight line as: "the shortest distance between two given points".
Yes, the distance between two points can be found if the longitude and latitude are known for both points. This can be calculated using the haversine formula, which takes into account the curvature of the Earth to determine the shortest distance between the two points.
The shortest path is a line perpendicular to the given line that passes through the given point.
If the two lines are parallel, then the shortest distance between them is a single, fixed quantity. It is the distance between any point on one line along the perpendicular to the line.Now consider the situation where the two lines meet at a point X, at an angle 2y degrees. Suppose you wish to find points on the lines such that the shortest distance between them is 2d units. [The reason for using multiples of 2 is that it avoids fractions].The points are at a distance d*cos(y) from X, along each of the two lines.
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Normally a straight line segment.
No. Given two points on a circle, the minor arc is the shortest arc linking them. The major arc is the longest.
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The question is curiously vague. Do the two lines exist in the same plane? If they do, then they must intersect somewhere -- unless they are parallel. For non-parallel lines, the distance between the two lines at the point of intersection is zero. For parallel lines, the shortest distance between them is the length of the line segment that is perpendicular to both. For intersecting lines, there is an infinite number of distances between the infinite number of pairs of points on the lines. But for any pair of points -- one point on line A and another on line B -- the shortest distance between them will still be a straight line. Given two lines in 3D (space) there are four possibilities # the lines are collinear (they overlap) # the lines intersect at one point # the lines are parallel # the lines are skew (not parallel and not intersecting) The question of "shortest distance" is only interesting in the skew case. Let's say p0 and p1 are points on the lines L0 and L1, respectively. Also d0 and d1 are the direction vectors of L0 and L1, respectively. The shortest distance is (p0 - p1) * , in which * is dot product, and is the normalized cross product. The point on L0 that is nearest to L1 is p0 + d0(((p1 - p0) * k) / (d0 * k)), in which k is d1 x d0 x d1.
The slope is calculated as: y1-y2/x1-x2 given two sets of points
Length is the distance - in given units - between two points on a line.