Yes. Draw a triangle without its base line. From both the base vertices draw a line to the opposite side(somewhere in the middle). The four lines so created will meet in 6 points.
It might depend on how you draw it, but I don't think it is possible. Draw the figure, and look at the points where lines meet. Count how many of those points are "odd", meaning that an odd number of lines meets there. Each of these points has to be either the starting point, or the end point, and you can only have one starting point and one end point.
Draw a rectangle and draw three lines in it.... Firstly, draw 3 lines and divide one line into two...then it will easy to draw a rectangle...
Draw two parallel lines of unequal length, and connect their end points. If you have a right angle, it is a right trapezoid. If the non-parallel sides are equal in length, it is an isosceles trapezoid.
2 lines
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One.
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Directly with no turns: 1 With turns: infinite
You cannot. At least, not one point. If the distance between the two given points is b, and the area of the triangle is A, then let h = 2A/b Then draw two lines parallel to the line formed by the two given points - one above and one below, each of these lines being at a distance h from the first line. Any point on either of these two lines will meet your requirements.
Yes,it is given that draw a rectangle with 3 lines so..1st draw a rectangle then put 3 lines inside in it....!!
one
draw lines
it depend upon the figure.only the can it be said that whether 9 lines can be made form 4 points.
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Yes. Draw a triangle without its base line. From both the base vertices draw a line to the opposite side(somewhere in the middle). The four lines so created will meet in 6 points.
Given a point, let's say (1,4) that you want to plot on the cartesian plane, find 1 on the x axis and 4 on the y axis. Now, draw lines up from the 1 and across from the 4. The place these two lines meet is the point (1,4). After you do it a few times, you will draw the lines in your head and not on paper.