i guess it is 18
You can have: 1 row of 36 2 rows of 18 3 rows of 12 4 rows of 9 or 6 rows of 6, so in total there are 5 ways.
1 row of 180 - 2 rows of 90 - 3 rows of 60 - 4 rows of 45 - 5 rows of 36 - 6 rows of 30 - 9 rows of 20 - 10 rows of 18 - 12 rows of 15 - 15 rows of 12 - 18 rows of 10 - 20 rows of 9 - 30 rows of 6 - 36 rows of 5 - 45 rows of 4 - 60 rows of 3 - 90 rows of 2 - 180 rows of 1 - total of 18 ways within the limits of the question
2 rows of 18 squares3 rows of 12 squares4 rows of 9 squares6 rows of 6 squares9 rows of 4 squares12 rows of 3 squares18 rows of 2 squares36 rows of 1 squareI would not count "1 row of 36 squares", because you only have a single row that cannot equal another row (there is only one rowafter all). If this is for homework, I would state your reasoning for excluding (or including) that set. Count all the options up, and you have 8 different ways you can arrange the rows with the exclusion.
12*1=12 12*2=24 12+24=36 There are 36 seats altogether in the bus
select 2 rows, the no. of rows you select will be the no. of rows to be inserted
36
never die is #36 unlimated ammo is #11
Two have 3 balls, two have 5 balls.
116 ÷ 2 = 58 even rows. There will also be 58 odd rows.
2
If we roll 2 dice simultanosly the sample space consists of 6 rows and 6 col so the answer is 6*6 i.e 36 elements.If we roll 6 dice simultanosly the sample space consists of 36 rows and 36 col so the answer is 36*36 i.e 1296 elements.