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For the principal quantum number ( n = 2 ), the possible values of the azimuthal quantum number ( l ) are 0 and 1 (since ( l ) can take on values from 0 to ( n-1 )). For each value of ( l ), the magnetic quantum number ( m_l ) can take values from (-l) to (+l). Therefore, for ( l = 0 ), ( m_l = 0 ) (1 combination), and for ( l = 1), ( m_l ) can be (-1, 0, +1) (3 combinations). In total, there are ( 1 + 3 = 4 ) possible combinations of ( l ) and ( m_l ) for ( n = 2 ).
What else can I help you with?
How many possible values for l and ml are there when n equals 4?
(N-1)=(4-1)= N=3 l=0,1,2,3
What are the possible values of ml for an electron in a d orbital?
The possible values of ml for an electron in a d orbital range from -2 to +2. This corresponds to the five orbitals in a d subshell: dz^2, dx^2-y^2, dxz, dyz, and dxy. Each orbital can hold up to two electrons with opposite spins.
How many possible values for l and ml are there when n equals 3?
I have essentially zero ability to answer that without seeing the equation. Another answer: n-1 = 3-1= 2 l=2 ml= -2,-1,0,1,2.
How many ml are in 30 ft?
Any answer possible: mL is a unit of volume, ft is a unit (obsolete) of length.
How many inches are 3.90 ml?
not possible to convert volume unit to length unit.
How many kilometers in 163 milliliters?
not possible to answer. km is unit of distance. ml is unit of volume.
How do i find range of 3.1 ml 2.7ml 4.6 ml 1.9 ml 8.7 ml?
You get the difference between the highest and lowest values, which are 8.7ml and 1.9ml. So 6.8ml is the range.
Values of n l and ml of 2p orbital?
n : 2 l : 1 ml : -1, 0, or 1
How many ml make 15 unit?
A ml is one unit, so 15 units of them would make 15 ml.
Which of the orbitals contains quantum number combinations that are not possible?
Any combination of quantum numbers that violates the Pauli exclusion principle is not possible. For example, having two electrons in the same orbital with all four quantum numbers (n, l, ml, ms) being the same is not allowed.
How many grid squares should you shade to represent 0.49 ml of Hydrogen peroxide?
That depends upon how many grid squares you have in total and the largest value you have to represent. Wherever possible, you should arrange that each square that you have to shade represents either a divisor or a simple fraction of all the values you have to represent. With 0.49 ml as one of the values, it is unlikely that the values you will have to represent are all multiples of 0.49 ml; nor are they all likely to be multiples of 0.07 ml. So unless you use 1 grid square to represent 0.01 ml you are going to have to shade a fraction of a grid square. Once you have chosen how much each grid square will represent, or have been given the value to use, divide the 0.49 by this value to find out how many grid square to shade: If each grid square represents 0.01 ml, shade 0.49 ÷ 0.01 = 49 of them If each grid square represents 0.02 ml, shade 0.49 ÷ 0.02 = 24 1/2 of them If each grid square represents 0.04 ml, shade 0.49 ÷ 0.04 = 12 1/4 of them If each grid square represents 0.05 ml, shade 0.49 ÷ 0.05 = 9 4/5 of them If each grid square represents 0.10 ml, shade 0.49 ÷ 0.10 = 4 9/10 of them etc.
What are the possible values of ml for each of the following values of l 0 1 2?
The magnetic quantum number ( m_l ) can take on integer values ranging from (-l) to (+l), including zero. For ( l = 0 ), ( m_l ) can only be ( 0 ). For ( l = 1 ), ( m_l ) can be (-1, 0, +1). For ( l = 2 ), ( m_l ) can take the values (-2, -1, 0, +1, +2).
