If you look at the formulas for volume of a cone and volume of a cylinder you can see that a cone will fit in exactly three times if the height and radius of the cone and cylinder are equivalent. A cone has the equation: (1/3)*pi*(r^2)*h=Volume. And a cylinder has the equation: pi*(r^2)*h=Volume. With h equaling height and r equaling radius, you can see that 3*(Volume of a cone)=Volume of a cylinder. Therefore, the cone would fit in three times if height and radius are equivalent for the two figures.
The volume of a cylinder is three times as much.
Volume of cylinder = PI r^2 h where r = radius and h= height Volume of Cone = (1/3) PI r^2 h where r=radius and h= height Therefore, the volume of a cone is one-third of the volume of a cylinder.
If the area of the base and the height of the cylinder and the cone are the same, then the volume of the cone will always be one third of the volume of the cylinder.
It is a cylinder
multiply the volume of the cylinder by 1/3. whatever you get is the volume of the cone
The cone has 1/3 of the volume of the cylinder.
The volume of a cone is 1/3 of the volume of a cylinder with the same radius and height
The volume of a cone is one third the volume of a cylinder of the same height. The volume of a cylinder is πr2h, so the volume of a cone is 1/3πr2h.
3x i think because the volume of a cone is one third of a cylinder of the same height and radius so if the volume is equal the height must be three times higher
Actually it isn't. That's the formula for a cylinder. A cone is 1/3 of that value.
Separate them into parts. First calculate the volume of the cylinder, then the cone and then add the results