A breaker protects the wire size of the feeder that is connected to it. The amperage of the load must be found. Without a voltage stated the amperage from the wattage given can not be calculated. The equation for amperage when the kw is given is A = kW x 1000/1.73 x volts x pf. The pf constant to use is .9.
I=270000/380/1.732 I=410A USE: 500A CIRCUIT BREAKER
AWG #3 copper.
7200
For a 13.8 kW electric heater at 208 volts, you would need a 3-phase circuit with a minimum of a 50-amp breaker to handle the load safely. This calculation is done by dividing the power (13,800 watts) by the voltage (208 volts) and then dividing by the square root of 3 (since it's a 3-phase system).
Calculate the ampereage at .8 pf and take a breaker of 150% of ampere nd set the over current protection at 125% of full load current.
To answer these types of questions, a voltage of the single phase motor should be stated. It has to do with the breaker sizing and wire sizing and current load.
Impossible to say without more details. It depends entirely on the voltage of the supply and whether it's single-phase or three-phase.
The formula you are looking for is I = W/E.
if you have 200 kva so it's 160 KW then ,you need 400 A MCCB and setting at 0.9 and use cable 4c.185 mm2 if the SMDB is nearby and all this will be change according to the ambient temperature and the electrical code used in your area
starting current of 315 kw motor in start delta 2.5 time for single sec. if your cable lingth 130 meter u can use 150mm2 (3 cable per phase) 150mm2 single cable current 292 Amp voltage drop 0.28/meters so u can use breaker 1000 Amp and set Im time (for starting current) setting avalible in breaker.
you need the current of motor or the KW/HP rating
Yes this size motor can be operated by bringing a 600 volt three phase supply to it.