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The graph of a logarithmic function in the form of F x equals logb x will always have a vertical asymptote at the y-axis and an x-intercept at the point?
The point you desire, is (1, 0).The explanation follows:b0 = 1, for all b; thus,logb(1) = 0, for all b.On the other hand, logb(0) = -∞,which explains the vertical asymptote at the y-axis.
Is it possible for graph of function to cross the horizontal assymptotes?
When you plot a function with asymptotes, you know that the graph cannot cross the asymptotes, because the function cannot be valid at the asymptote. (Since that is the point of having an asymptotes - it is a "disconnect" where the function is not valid - e.g when dividing by zero or something equally strange would occur). So if you graph is crossing an asymptote at any point, something's gone wrong.
Which statement is a correct interpretation of the vertical line test?
A-If there exists a vertical line that intersects the graph at exactly one point, the graph represents a function.B-If there exists a vertical line that intersects the graph at exactly one point, the graph does not represent a function. C-If there exists a vertical line that intersects the graph at more than one point, the graph represents a function.-DIf there exists a vertical line that intersects the graph at more than one point, the graph does not represent a function
Is it true that the function has a vertical asymptote at every x value where its numerator is zero and you can make a table for each vertical asymptote to find out what happens to the function there?
Every function has a vertical asymptote at every values that don't belong to the domain of the function. After you find those values you have to study the value of the limit in that point and if the result is infinite, then you have an vertical asymptote in that value
When can you say that the graph is function or mere relation?
If a vertical line intersects the graph at more than one point then it is not a function.
How can you tell if a graph is a function?
A graph is a function if every input (x-value) corresponds to only one output (y-value). One way to check for this is to perform the vertical line test: if a vertical line intersects the graph at more than one point, the graph is not a function.
A graph is not a function if the vertical line intersects the graph at more than point?
Not calculus, but correct. This is known as the vertical line test and is used to teach the basics of defining a function.
Why does f represent the graph of a function?
Because each vertical lines meets its graph in a unique point.
How do you determine whether a graph a mathematical relationship is a function?
Draw a vertical line if the line hits more than one point on the graph then it is not a function.
How do I determine the domain and the equation of the vertical asymptote with the equation f of x equals In parentheses x plus 2 end of parentheses minus 1?
The domain of the function f(x) = (x + 2)^-1 is whatever you choose it to be, except that the point x = -2 must be excluded. If the domain comes up to, or straddles the point x = -2 then that is the equation of the vertical asymptote. However, if you choose to define the domain as x > 0 (in R), then there is no vertical asymptote.
When does a graph represents a function?
take a vertical line, if another line intersects that vertical line at 2 points, then it is a function.In other words,a graph represents a function if each vertical line meets its graph in a unique point.
Is a parabola a function?
Y = X2 ===== The graph of this parabola is crossed only at a point and once by a vertical line, so it is a function. Passes the vertical line test.
