The point you desire, is (1, 0).The explanation follows:b0 = 1, for all b; thus,logb(1) = 0, for all b.On the other hand, logb(0) = -∞,which explains the vertical asymptote at the y-axis.
When you plot a function with asymptotes, you know that the graph cannot cross the asymptotes, because the function cannot be valid at the asymptote. (Since that is the point of having an asymptotes - it is a "disconnect" where the function is not valid - e.g when dividing by zero or something equally strange would occur). So if you graph is crossing an asymptote at any point, something's gone wrong.
A-If there exists a vertical line that intersects the graph at exactly one point, the graph represents a function.B-If there exists a vertical line that intersects the graph at exactly one point, the graph does not represent a function. C-If there exists a vertical line that intersects the graph at more than one point, the graph represents a function.-DIf there exists a vertical line that intersects the graph at more than one point, the graph does not represent a function
Every function has a vertical asymptote at every values that don't belong to the domain of the function. After you find those values you have to study the value of the limit in that point and if the result is infinite, then you have an vertical asymptote in that value
An undefined graph typically occurs when there is a division by zero in a mathematical equation, resulting in an infinite or undefined value. In a graph, this would manifest as a vertical line or asymptote where the function approaches infinity or negative infinity. This can happen, for example, when plotting the graph of a rational function where the denominator equals zero at a certain point.
If a vertical line intersects the graph at more than one point then it is not a function.
A graph is a function if every input (x-value) corresponds to only one output (y-value). One way to check for this is to perform the vertical line test: if a vertical line intersects the graph at more than one point, the graph is not a function.
Not calculus, but correct. This is known as the vertical line test and is used to teach the basics of defining a function.
Because each vertical lines meets its graph in a unique point.
Draw a vertical line if the line hits more than one point on the graph then it is not a function.
The domain of the function f(x) = (x + 2)^-1 is whatever you choose it to be, except that the point x = -2 must be excluded. If the domain comes up to, or straddles the point x = -2 then that is the equation of the vertical asymptote. However, if you choose to define the domain as x > 0 (in R), then there is no vertical asymptote.
take a vertical line, if another line intersects that vertical line at 2 points, then it is a function.In other words,a graph represents a function if each vertical line meets its graph in a unique point.