Yes, a vertical asymptote represents a value of the independent variable (usually (x)) where a function approaches infinity or negative infinity, and the function is indeed undefined at that point. This is because the function does not have a finite value as it approaches the asymptote. Thus, the vertical asymptote indicates a discontinuity in the function, where it cannot take on a specific value.
2
It will have the same asymptote. One can derive a vertical asymptote from the denominator of a function. There is an asymptote at a value of x where the denominator equals 0. Therefore the 3 would go in the numerator when distributed and would have no effect as to where the vertical asymptote lies. So that would be true.
I don't know, what?
The slope of any vertical Line is undefined because anything divided by zero is undefined.
A vertical line.
Undefined
No. For example, in real numbers, the square root of negative numbers are not defined.
2
It will have the same asymptote. One can derive a vertical asymptote from the denominator of a function. There is an asymptote at a value of x where the denominator equals 0. Therefore the 3 would go in the numerator when distributed and would have no effect as to where the vertical asymptote lies. So that would be true.
An undefined slope is vertical.
no
I don't know, what?
One way to find a vertical asymptote is to take the inverse of the given function and evaluate its limit as x tends to infinity.
It remains a vertical asymptote. Instead on going towards y = + infinity it will go towards y = - infinity and conversely.
It can.
A vertical line has an undefined slope.
The slope of any vertical Line is undefined because anything divided by zero is undefined.