graph the inequality 5x+2y<4
A bivariate linear inequality.
we should prevent inequality by
The shaded region above or below the line in the graph of a linear inequality is called the solution region. This region represents all the possible values that satisfy the inequality. Points within the shaded region are solutions to the inequality, while points outside the shaded region are not solutions.
When graphing a linear inequality, the first step is to replace the inequality symbol with an equal sign to graph the corresponding linear equation. This creates a boundary line, which can be solid (for ≤ or ≥) or dashed (for < or >) depending on whether the points on the line are included in the solution set. After graphing the line, you then determine which side of the line represents the solution set by testing a point (usually the origin if it's not on the line) to see if it satisfies the original inequality. Finally, shade the appropriate region to indicate the solutions to the inequality.
The Feasible Region
The question cannot be answered because there is no inequality there!
The inequality (6x + 2y - 10 > 0) can be rewritten in slope-intercept form as (y > -3x + 5). The boundary line is (y = -3x + 5), which has a slope of -3 and a y-intercept of 5. The region above this line represents the solution set for the inequality. Since the inequality is strict (>), the boundary line itself is not included in the solution.
it is called a half plane :)
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
The graph is a region of the space on one side or another of the related function. If the inequality is strict then the related function itself is not part of the solution; otherwise it is.
Linear programming is just graphing a bunch of linear inequalities. Remember that when you graph inequalities, you need to shade the "good" region - pick a point that is not on the line, put it in the inequality, and the it the point makes the inequality true (like 0