The inequality (6x + 2y - 10 > 0) can be rewritten in slope-intercept form as (y > -3x + 5). The boundary line is (y = -3x + 5), which has a slope of -3 and a y-intercept of 5. The region above this line represents the solution set for the inequality. Since the inequality is strict (>), the boundary line itself is not included in the solution.
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If the equal sign in a linear equation in two variables is replaced with an inequality symbol, the result is a linear inequality in two variables. 3x-2y>7 x<-5
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It is a set of three expressions , two variable and one constant. There are no operations defined for them, not any symbols of equality or inequality.
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You draw the graph of the straight line x + 2y = 5.Evaluate the inequality at the origin: 0 + 2*0 > 5 or 0>5. This is not true so the part of the plane NOT containing the origin (above and to the right of the line) is the valid region.Also, since it is a strict equality, the line itself is not part of the valid region.