11
(9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99)
Those numbers divisible by 9 are the multiple of 9; thus need to know how many multiples of 9 there are between 1 and 100:
100 ÷ 9 = 11 r 1 ÷ last multiple of 9 is 11 × 9 (= 99)
→ There are 11 - 1 + 1 = 11 numbers between 1 and 100 which are divisible by 9.
(They are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.)
There are 98 numbers are between 1 and 100 that are divisible by five.
There are a total of 14 numbers between 0 & 100 that are divisible by 7.
There are nine numbers between 10 and 100 that are evenly divisible by 11.
There are 49 numbers between 1 and 100 that are divisible by two.
There are 14 numbers between 1 & 100 that are divisible by 7.
prime numbers between 0 -100 which are divisible by 7: 7
There are 27 numbers between 1 and 100 that are divisible by three but not by five.
There are 66 numbers between 1 and 100 that are divisible by two or three.
33 numbers between 1 and 100 are divisible by 3.
Since 100/4 = 25, there are 25 numbers between 0 and 100 divisible by 4.
there are 17 divisible by 3 between 50 to 100 , 51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99
100 ÷ 4 = 25 → 24 numbers between 0 and 100 exclusive are divisible by 4 100 ÷ 6 = 16 2/3 → 16 numbers between 0 and 100 are divisible by 6 lcm(4, 6) = 12 → 100 ÷ 12 = 8 1/3 → 8 numbers between 0 and 100 are divisible by 4 and 6.