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Q: How many numbers up to 100 are divisible by 7?

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They are the 3333 numbers that are divisible by 3 without remainder.

Clearly, both 810 and 910 are divisible by 5. A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3. In your example, 810 components add up to 9, which is divisible by 3. But the components of 910 add up to 10 which is not so divisible.

Prime numbers go on forever.

No, even numbers are evenly divisible by two, which means that only the multiples of two are even numbers. Odd numbers make up the other integers. There is no such thing as an odd or even decimal.

There are 25 prime numbers up to 100. They are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.

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25

The numbers divisible by nine up to a 100 are 9,18,27,36,45,54,63,72,81,90,and,99

Any of its multiples up to 100

100 is divisible by 5. The next is 105, the next is 110, and so on forever.

Any number ending in a 5 or 0 !

Just count up all the even numbers which will all be divisible by 2

Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33

There are 80 such numbers.

Multiples of 3 in that range start at 102 and continue every three numbers forever.

Depending on how you look at it, there are either 99 or 100 whole numbers up to 100. If you mean up to and including 100, then the answer is 100 whole numbers, if not, then the answer is 99 whole numbers.

There are 25 prime numbers up to 100.

Only up to 7. 9 is divisible by 3. after that some odd numbers are divisible and some aren't.

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