68 is divisible by 17 but not by 3.
The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 The factors of 68 are: 1, 2, 4, 17, 34, 68
Well, like any other real number, 68 is divisible by any number except for 0, as division by zero is undefined. 68 is evenly divisible (with no remainder) by: 1; 2; 4; 17; 34; 68 [hope I did not miss any]
no
2,4,1,68
No. 68 is not evenly divisible by 15.
No because 68/13 is 5.23076923
68. 68 is divisible by 17.
3,468
Both 51 and 68 are divisible by 17, so that would simplify to 3/4.
Any number of the form 68*k where k is an integer.
No. 1+9+6=16, which is not divisible by 3; 1+4+6=11, which isn't divisible by 3 either. No. 1+9+6=16, which is not divisible by 3; 1+4+6=11, which isn't divisible by 3 either.