1 1
2 10
3 11
4 100
5 101
6 110
7 111
No one on this site will know how do this. It's far too complicated, as for me I think you need to figure out how to do this yourself.
Eight binary user digits refer to a sequence of eight binary digits (bits), which can be either 0 or 1. This combination allows for a total of 2^8, or 256, different possible values or combinations. Each bit represents a power of 2, ranging from 2^0 to 2^7, enabling the representation of numbers from 0 to 255 in binary form. Binary digits are fundamental in computing and digital communications, as they form the basis of data representation.
As per the 8421 rule the given binary number can be solved as : 0 0 0 0 0 1 1 1 0 0 0 0 0 4 2 1 i.e : 4+2+1 = 7 So the answer is 07 in decimal for 00000111 in binary
To find the next number in the sequence -1, 8, 1, 4, 7, 0, 7, 0, we can observe the pattern in the differences between the numbers. The differences are: 9, -7, 3, 3, -7, 7, -7. The pattern suggests the next difference might continue with the established sequence, leading to 7 + (-7) = 0. Therefore, the next number is likely 0.
That all depends upon the first term of the sequence: As long as the first number is less than, or equal to 777 and as long as (first_number MOD 7) ≡ (777 MOD 7) will 777 be in the sequence. 777 MOD 7 ≡ 0 ⇒ if, and only if, first_number ≤ 777 and first_number MOD 7 ≡ 0 (ie 7 divides the first number) will 777 be in the sequence.
Binary numbers should start with 1 as 0 means that there is nothing in the column. So 00000111 is really just 111, which is the binary equivalent of the number 7
215
7 in Binary is 111
A 3-bit binary number can represent values from 0 to 7. Each bit can be either 0 or 1, so the possible combinations are 000 (0), 001 (1), 010 (2), 011 (3), 100 (4), 101 (5), 110 (6), and 111 (7). Thus, the 3-bit binary equivalent can be any of these eight values.
It all depends. You need 3 bits to get 8 potential States. 000 001 010 011 100 101 110 111 From top to bottom this counts from 0 to 7 in binary. In this example, the LSB for the sequence above would be 0, 1, 0, 1, 0, 1, 0 and 1. You really have to look at the overall decoding scheme. If you had a device with 7 inputs then you could assign each input to a specific segment. Depends on what you have to amswer your question precisely.
Decimal has ten different digits - 0 1 2 3 4 5 6 7 8 9 Binary only has two different digits - 0 1
To convert binary to hexadecimal split the binary number into blocks of 4 bits from the right hand end; each block represents a hexadecimal digit: 111101110001 → 1111 0111 0001 = 0xF71