You need to apply Heron's Formula here which states:
Square-root( s*(s-a)*(s-b)*(s-c) ) where s = 1/2(a+b+c) and a,b and c are your side measurements.
so your s = 1/2(37+30+24)=1/2 (91) = 45.5
input into Heron's formula;
square-root( 45.5*(45.5-37)*(45.5-30)*(45.5-24) )
and you can finish the rest from here its simple calculator work.
The measure of the hypotenuse of a right triangle if one side is 24 inches and other side is 30 inches is: 38.42 inches.
YES. 18 and 24 are the two leg lengths and 30 is the hypotenuse then by Pythagoras' Theorem :- 182 + 242 = 302 324 + 576 = 900......which is true and therefore the three side lengths 18, 24 and 30 do form the sides of a right-angled triangle.
For the 6:8:10 triangle, area = perimeter = 24. Also, for the 5:12:13 triangle, area = perimeter = 30. Whether these are indeed the only examples I am not sure. That would take some proving.
For the 6:8:10 triangle, area = perimeter = 24. Also, for the 5:12:13 triangle, area = perimeter = 30. Whether these are indeed the only examples I am not sure. That would take some proving.
Same as you would find the area of any triangle A = (1/2)[base][height]
To get the area of an equilateral triangle, you just need to know the length of one side. Multiply the length of one side by the square root of three and then divide the product by four, and you will get the area of the triangle.
If you only have the measures of angles, you cannot find the area. You must know at least one side.
No, because 8 isn't a factor of 30.
The dimensions given would not form a triangle. The sum of a triangles 2 smallest sides must be greater than the triangle's longest side.
Just find the length of the bottom side. If you're looking for how to solve it with algebra, given: Area=30 and Height=4 Remember: Area of a triangle = 1/2 (base ) x (height) Then write the equation: 30 = 1/2 (base) x (4) To solve it, divide each side by 2 : 15 = (base)
The area is 30 units2
38.42