Assuming mean average:
average = sum/number_of_items
→ 10 = sum/2
→ sum = 10 x 2 = 20
So any two numbers with a sum of 10 have a mean average of 10, eg {5, 15}, {1, 19}, {0, 20}, {-5, 25}, etc.
With the median average, for two numbers it is exactly the same as the mean average, so any pair of numbers that sum to 20 will do.
With the mode average, only the case of the pair of numbers {10, 10} will suffice.
0.5
The halfway point between two numbers is found by calculating the average of the two numbers. In this case, the average of -20 and 10 is (-20 + 10) / 2 = -10 / 2 = -5. Therefore, the number halfway between -20 and 10 is -5.
20
Avreage = Sum/number of values So 10 = sum/2 Multiply both sides by 2: 20 = sum
There is not enough information. For example, 2 numbers, whose average is 10 could be -50 and 70 or 10 and 10 or 9 and 11 or 7.5 and 12.5 etc. All that you know in this case is that the sum of the two numbers = average*number of values = 10*2 = 20
If the average is 10 then 15 is 5 above average.
If its a even number of numbers, find the average of the middle two. = 9.5
The average number of toes for an American is 10, as most people have 10 toes (5 on each foot).
hi
Two primes are symmetric primes of a natural number (n) if their average is n. For example 10, has two pairs of symmetric primes. 7 and 13, and 3 and 17 because their averages are 10.
You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...
8+10+12=30 30/3=10 10 is the average of 8 12 and 10 If that's 812 and 10, the average is 411. If that's 8, 12 and 10, the average is 10.