The equation you have written is not formatting in the way I think you intended it to be.
3x - y - 6x(y^2) is what I assume you mean?
3x - y = 6xyy
3x - 1 = 6xy
3 - (1/x) = 6y
(1/2) - (1/6x) = y
y = (1/2) - (1/6x)
To find the slope from tables using Kuta Software's Linear Graphing LG3, identify two points from the table, typically in the form (x1, y1) and (x2, y2). The slope (m) can be calculated using the formula ( m = \frac{y2 - y1}{x2 - x1} ). This represents the change in y divided by the change in x between the two points. Repeat this process with different pairs of points to verify consistency in the slope.
Y1=2x^(2/3)+√(20-x²)-3 Y2=2x^(2/3)-√(20-x²)-3
No, linear equations don't have x2. Equation with x and y are usually linear equations. Equations with either x2 or y2 (but never both) are usually quadratic equations.
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
table of values,x and y-intercept and slope and y-intercept
if we take the (x1,y1),(x2,y2) as coordinates the formula was (x-x1)/(x2-x1)=(y-y1)/(y2-y1)
No, not if the y is squared. When graphed the equation will not form a straight line.
0
An equation is linear if the highest power of the unknown in the equation is 1for example an equation with just a variable to the power one such as x, y and so on is linear but one with x2, y2 and above is not linear
Yes, as x-y2=0
Any function of the form:f(x) = mx + b where "m" is the slope, and "b" is the y-intercept.
X2+y2=25 (x-8)2+y2 =41