Area of a rectangle: length times width
Width=11
Length= 11x3= 33
11x33= 363 square feet
the length is equal to 160,083
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
15 feet.
63 feet
the base of the rectangle exceeds three times its altitudes by 4. if the length of the side of the square is 8centimeter find the dimension of the rectangle.
9
Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63
Width: 8.5 Length: 25.5
64 meters
dont is answer
The length is 12 cm and the width is 4 cm and so 12*4 = 48 square cm
It is the area of the rectangle which is length times width