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first you multiply 33333333334 by 33333333334

(if its kinda hard to count these, they both have ten 3's, and one 4)

and then you should get this:

1111111111155555555556

(for this one, there are eleven 1's, ten 5's, and one 6)

then you add all these digits together, and should get this:

67

***p.s. the reason why it's not 1156 is because, in the order of operations, you have to solve the exponents (to the second power) before you can start adding***

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15y ago
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6mo ago

The sum of the digits of 33333333334 is 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 4 = 30. When this sum is squared, the result is 30^2 = 900.

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Q: Find the sum of the digits of 33333333334 to the second power?
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