4a - 5b = 74a +5b = 17From the first equation:4a = 7 + 5bsubstitute this value in the second equation:7 + 5b + 5b = 177 + 10b = 1710b = 10b = 1Now,solve for a :4a - 5(1) = 74a = 7 + 54a = 12a = 3
The value of -3 to the second power is 9.
3 to the second power is 32 or 3 x 3 which is 9
If you mean: 4a-3 = 2a+7 then the value of a works out as 5
4a+3 when a=34(3)+312+3=15So you are substituting(replacing) 'a' with the known value of '3'. You then multiply the '4' with the '3' because of the placing of 'a'.
4a+3-a =12 4a-a = 12-3 3a = 9 a = 3
5
Multiply. 2 x 2 x 3 x 3 = 36
a = -2-4a/3-2 = 8-4a = 8(3-2) times both sides by (3-2)-4a = 24-16-4a = 8-a = 2 divide both sides by 4a = -2 times both sides by -1
4a
10a − 3 − 4a
4a7 / 3a3 = ( 4/3 ) x ( a7/a3 ) = 4a4 / 3
4a x 3
2a*3 = 8+4a 6a = 8+4a 6a-4a = 8 2a = 8 a = 4
4a - 5b = 74a +5b = 17From the first equation:4a = 7 + 5bsubstitute this value in the second equation:7 + 5b + 5b = 177 + 10b = 1710b = 10b = 1Now,solve for a :4a - 5(1) = 74a = 7 + 54a = 12a = 3
It is not clear whether the question is 3a + 4a + 5a + 6a^3 which would be 12a + 6a^3 or 3a + 4a + 5a + (6a)^3 = 12a + 216a^3 or (3a + 4a + 5a + 6a)^3 = 5832*a^3 But none of these really require summation notation!
4a + 3a = (4 + 3)a = 7a