A 1450 watt coffee maker will use around 13 amps at 110 volts.
To answer this question a voltage value must be stated. Divide the voltage into 50 KVA and your answer will be in amps.
3/0 gauge
AWG # 14 is the smallest wire you can install in a home and it can only be used in living areas. It will carry 15 amps.
The equation for amperage when the kilowatts are known is Amps = kVA x 1000/1.73 x Volts.The electrical code states that a feeder for a transformer has to be rated at 125% for the primary and secondary load amperages.The amperage on the primary needed to supply a 70 KVA three phase transformer to its full capacity at 600 will be 68 amps. 68 x 125% = 85 amps. A #4 copper conductor with an insulation factor of 90 degrees C is rated at 95 amps.The amperage on the secondary needed to supply a 70 KVA three phase transformer to its full capacity at 480 will be 84 amps. 84 x 125% = 105 amps. A # 3 copper conductor with an insulation factor of 90 degrees C is rated at 115 amps.
6 AWG will handle 50 amps with a voltage drop of about 4 volts. If you go to 4 AWG and limit to 50 amps your voltage drop will be 2.5 volts.
The average 10 cup coffee maker uses around 8 amps.
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A typical Keurig coffee maker uses between 8 to 12 amps, depending on the model and features. Most home models operate at around 120 volts, which translates to a power consumption of approximately 960 to 1440 watts. It's always a good idea to check the specific model's specifications for the exact amperage.
You can calculate the amperage by dividing the wattage by the voltage. If the roaster is rated at 1450 watts and assuming a standard voltage of 120V in most households, the amperage would be approximately 12.08 amps (1450 watts / 120 volts = 12.08 amps).
To determine the watts of power, multiply voltage x amperage. In this case, 120 volts x 10 amps- which is 1200 watts.
You cannot increase voltage by adding amps.
There is no formula needed, they are the same thing, just two different wordings.
To answer this question a voltage value must be stated. Divide the voltage into 50 KVA and your answer will be in amps.
13 amps should be a dedicated outlet since one outlet has a maximum capacity of 15 amps <<>> If the supply voltage is 120 volts then the amperage is I = W/E. Amps = Watts/Volts = 1450/120 = 12.08 amps.
The maximum current rating for the circuit breaker needed for a device that operates at 20 amps is 25 amps.
The guage of wire for 20 amps is #12 copper.
3 things Volts, ohms, and amps