Commonwealth Act 294
18: 209-219-229-239-249-259-269-279-289 and 290-291-292-293-294-295-296-297-298 (but not 299)
The function of the adjusting ring is to adjust the blowdown pressure of the safety valve. By ASME rules this must be adjusted to 2% of the set pressure, or a minimum of 2 psi. If the valve is set to lift at 100 psig or less then the blowdown must be set at 2 psi. If higher then it must be set at 2%. Thus, for a safety valve that lifts at 300 psig, the blowdown will be set (at 2%) such that the valve will reseat when the pressure drops to 294 psig. In many states that have adopted ASME rules, these settings cannot be changed except by an authorized safety valve repair shop holding a National Board repair or assembly "V" or "VR" stamp.
class Node 002 { 003 private: 004 int data; 005 006 public: 007 friend class List; 008 friend class stack; 009 010 Node* next; 011 012 Node(){data = 0;} 013 014 Node(int x) 015 { 016 next = 0; 017 setdata(x); 018 } 019 020 int getdata() 021 { 022 return data; 023 } 024 025 void setdata(int x) 026 { 027 data = x; 028 } 029 030 void print() 031 { 032 cout<<data; 033 } 034 035 ~Node(){} 036 }; 037 038 class List 039 { 040 private: 041 Node* Head; 042 Node* Tail; 043 044 public: 045 046 friend class stack; 047 List(){Head = 0; Tail = 0;} 048 049 void addnode(int x) 050 { 051 Node *current = new Node(x); 052 053 if(Head 0) 197 { 198 return true; 199 } 200 else 201 { 202 return false; 203 } 204 } 205 206 Node* topEl() 207 { 208 return (L.top()); 209 } 210 211 void printstack() 212 { 213 L.printlist(); 214 } 215 216 ~stack() 217 { 218 L.deletelist(); 219 } 220 221 }; 222 223 int main() 224 { 225 stack operand1; 226 stack operand2; 227 stack carry; 228 stack result; 229 int tempsum; 230 int a,b,c; 231 int carry1; 232 Node *n1 = NULL; 233 Node *n2 = NULL; 234 Node *n3 = NULL; 235 236 operand1.push(3); 237 operand1.push(8); 238 operand1.push(0); 239 operand2.push(5); 240 operand2.push(3); 241 operand2.push(5); 242 243 244 245 while(!(operand1.isEmpty()) && !(operand2.isEmpty())) 246 { 247 n1 = operand1.topEl(); 248 a = n1->getdata(); 249 n2 = operand2.topEl(); 250 b = n2->getdata(); 251 tempsum = a + b; 252 253 if(tempsum > 9) 254 { 255 c = 0; 256 if(!(carry.isEmpty())) 257 { 258 n3 = carry.topEl(); 259 c = n3->getdata(); 260 carry.pop(); 261 } 262 carry1 = tempsum / 10; 263 tempsum = tempsum % 10; 264 carry.push(carry1); 265 result.push(tempsum + c); 266 } 267 else 268 { 269 if(!(carry.isEmpty())) 270 { 271 n3 = carry.topEl(); 272 c = n3->getdata(); 273 result.push(tempsum + c); 274 carry.pop(); 275 } 276 else 277 { 278 result.push(tempsum); 279 } 280 } 281 operand1.pop(); 282 operand2.pop(); 283 } 284 285 n1 = operand1.topEl(); 286 a = n1->getdata(); 287 n2 = operand2.topEl(); 288 b = n2->getdata(); 289 tempsum = a + b; 290 if(carry.isEmpty()) 291 { 292 result.push(tempsum); 293 } 294 else 295 { 296 n3 = carry.topEl(); 297 c = n3->getdata(); 298 result.push(tempsum + c); 299 carry.pop(); 300 } 301 operand1.pop(); 302 operand2.pop(); 303 304 result.printstack(); 305 306 system("pause"); 307 return 0; 308 }
It is 49 times 6 = 294
294
294
294 divided by 2
294
294 minutes.
147n = 294Divide each side by 147:n = 294/147 = 2
The distance in New York from Oswego to Bronx is 294 miles. That equals 473 kilometers and about 4-3/4 hours in driving time.
There are many possible answers. One of the simpler ones to remember is 1 times 294.
Prime decomposition of 294: 294 = 2 x 3 x 7^2 Other ways of writing 294: 294 = 1 x 294 294 = 2 x 147 294 = 3 x 98 294 = 6 x 49 294 = 7 x 42 294 = 14 x 21
It will take about 4 hours 45 minutes to drive the 294 miles.
95 plus 52 plus 95 plus 52 equals 294.