C program to check given number is a perfect square or not?

Answer 1

#include <stdio.h>

#include <math.h>

int main(void)

{

int number;

double result;

printf ("\n Introduce an integer: ");

scanf ("%i", &number);

result= sqrt (number);

if ((result * result)== number)

printf ("\n The integer HAS a perfect square \n\n");

else

printf ("\n The integer DOES NOT HAVE a perfect square \n\n");

getch ();

}

Shrikanth Ganure

The Oxford College of Engineering (MCA-2010 Batch)

Bangalore..

Answer 2

#include

main()

{

int a;

print f("enter the element of a");

scan f("%d",&a);

if(a^2==4)

print f("it is a perfect square");

else

print f("not a square");

getch();

}

Its not working.......... I am done the program

#include

#include

void main()

{

int a,b;

clrscr();

printf("Enter the num");

scanf("%d",&a);

b=sqrt(a);

if((b*b)==a)

printf("The given number %d is perfect square",a);

else

printf("The given number is not a perfect square");

getch();

}

Answer 3

echo "enter a number"

read num

i=1

per=0

while [ $i -le $num ]

do

tmp=`expr $num % $i`

if [ $tmp -eq 0 ]

then

per=`expr $per + $i`

fi

i=`expr $i + 1`

done

per=`expr $per - $num`

if [ $per -eq $num ]

then

echo "$num is a perfect number!!!"

else

echo "$num is not a perfect number!!!"

fi