Design the logic code for program to print numbers in reverse order from 10 down to 1?

Answer 1

Enter values and end of the list enter -1 to see output. but execute it at command line.

<?php

function readData(){

fwrite(STDOUT, "Please enter your name\n");

// Read the input

$name = fgets(STDIN);

if($name != -1)

readData();

fwrite(STDOUT, "Hello $name");

return;

}

readData();

?>

start

num Sub

num Size = 10

index = 0

while index<10

index = index + 1

endwhile

while index > 0

index = index - 1

endwhile

print Sub

stop

Answer 2

This is C++ Code:

#include <iostream>

using namespace std;

int main()

int x = 10;

for(int i = 0; i > 0; i++)

cout << x;

x = x - 1;

return 0;

-- this might be something easier to understand:

start

num Sub

num Size = 10

index = 0

while index<10

index = index + 1

endwhile

while index > 0

index = index - 1

endwhile

print Sub

stop

Answer 3

/n make by dibyendu/n

#include<stdio.h>

#include<conio.h>

main()

{

int j,n;

clrscr();

printf("Enter a number");

scanf("%d",&n);

for(j=n;j>=0;j--)

{

printf("%d\n",j);

}

getch();

}

Answer 4

First, create an array to hold the answers:

int answers [10] ;
int count = 0 ;

The count will contain the index into the number of answers given. Then, after all the values have been input, simply count backward in a loop to give the reversed order of entering:

for (int x = count; x > 0; x--)
{
printf ("Value : %d\n", answers [x]) ;
}

That's it!

Answer 5

import java.util.*;

class reverse

{

public static void main(String args[])

{

System.out.println("Enter the elements ");

for(int i=0;i<10;i++)

int a[i]=sc.nextInt();

System.out.println("you entered the array is");

for(int i=0;i<10;i++)

System.out.println(a[i]);

System.out.println(" the reverse order array is");

for(i=9;i>=0;i--)

System.out.println(a[i]);

}

}

Answer 6

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j;

clrscr();

for(i=1;i<10;i++)

{

printf("%d\t",i);

}

for(j=10;j>=1;j--)

{

printf("%d\t",j);

}

getch();

}

Answer 7

Pseudo-code is an informal method of describing an algorithm in language, but the chosen language can be anything. Key to pseudo-code is to describe the algorithm unambiguously and intuitively, and free from knowledge or constrains of a particular human language or programming language.

As an example, an algorithm which counts down from 10 to 1 could be described like so:

for each whole number N, counting down from 10 to 1 in steps of 1:

print N next number N

Answer 8

The simplest solution is to use a stack

stack s

// input 10 numbers

for i = 1 to 10 inclusive

input n

s.push (n)

next i

// print numbers in reverse order

for i = 1 to 10 inclusive

print s.top()

s.pop()

next i

Answer 9

int i=10;

while (i>0) {

printf ("%d\n", i);

i--;

}

Answer 10

let n = 10

while n >= 1

{

print n

let n = n - 1

}

end while