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You are a 4 digit number your thousands digit is twice your ones digit your hundreds digit is four times your thousands digit and your tens digit is the sum of your ones and thousands digit what numbe?
1.382 OR 0.000 or 2831
EBNF float data type?
<float_literals> -> <digit> { <digit> } [ . ] [ { <digit> } ] <digit> -> "0" | <digit excluding zero> <digit excluding zero> -> "1" | "2" | "3" | "4" | "5" | "6" | "7" | "8" | "9" hi dude i wish you are satisfied with my answer LOL ^^
How can capacitive reactance be calculated?
it depends on capacitance and frequency, both inversely. Check your AC circuits textbook for the exact equation.
What is the program to figure out how many numbers from 0 to 9 are needed for 1 to 89 for example?
#include<iostream> #include<array> #include<sstream> std::array<int,10> get_frequency (int range_min, int range_max) { if (range_max<range_min) std::swap (range_min, range_max); std::array<int,10> digit {}; for (int count {range_min}; count<=range_max; ++count) { std::stringstream ss {}; ss << count; std::string s {}; ss >> s; for (auto c : s) { ++digit[c-'0']; } } return digit; } int main () { std::array<int,10> digit {}; digit = get_frequency(1, 89); std::cout << "In the range 1 to 89...\n"; for (int d {0}; d<10; ++d) { std::cout << "\tthe digit " << d << " appears " << digit[d] << " times.\n"; } } Output: In the range 1 to 89... the digit 0 appears 8 times. the digit 1 appears 19 times. the digit 2 appears 19 times. the digit 3 appears 19 times. the digit 4 appears 19 times. the digit 5 appears 19 times. the digit 6 appears 19 times. the digit 7 appears 19 times. the digit 8 appears 19 times. the digit 9 appears 9 times.
What is the last digit of pie?
Pi doesn't have a last digit - it goes on for infinity (it also doesn't seem to repeat itself, so there can't even be a philosophical argument for the last digit).
