You can do 4 rows and 13 columns and you get 52.
product = sizeof (char [4][13]);
of course it is just a joke, in actual code you write
product = 4*13;
Use the array suffix operator ([]), or use a pointer offset from the start of the array, such that an offset of 1 is equivalent to the size of an array element (all elements in an array must be of equal size). The latter method is what actually goes on behind the scenes when using the array suffix operator, but the former is generally easier to use.
C provides rectangular multidimensional arrays. In C, a two-dimensional array is really a one-dimensional array, each of whose elements is an array. An array is initialized by a list of initializations in braces; each row of a two-dimensional array is initialized by a corresponding sub-list. Example of two dimensional array initialization: char array_example[2][4] = { {11, 12, 13, 14}, {21, 22, 23, 24} };
main void void void (void) { float temp1 [13]= {1,4,2,3,4,5,7,88,9,4,3,23,12};
Ah, arrays are like magical palettes where you can organize and store multiple items in one place. Imagine a lovely garden with 13 different flowers, each in its own spot but all part of the same beautiful landscape. In the world of programming, an array for 13 would be a collection that can hold 13 elements, making it easier to work with and manage those items together. Just like painting a happy little picture, arrays help keep things nice and tidy.
An array is simply a contiguous block of memory. The length of that memory is the product of all its dimensions multiplied by the size of its type. Thus a 5x5 array is exactly the same as a 1x25 array. The only difference is in how you refer to each element. The following code demonstrates how we can remap a 5x5 array to a 1x25 array, simply by pointing at the first element. Note that we haven't actually changed the array, nor have we copied it to new memory. We're simply interpreting the exact same memory in two different ways. #include<iostream> #include<iomanip> int main() { int x[5][5] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25 }; // treat as 5x5 array: for (int a=0; a<5; ++a) { for (int b=0; b<5; ++b) { std::cout<<std::setw (3)<<x[a][b]; } std::cout<<'\n'; } std::cout<<std::endl; // treat as one-dimensional array (remap) int* y = x[0]; for (int c=0; c<25; ++c) std::cout<<std::setw (3)<<y[c]; std::cout<<'\n'<<std::endl; } Output: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
1 x 13
13 is a prime number because u cant find 13 as a product on a multiplication!
To find the product when the sum of 59 and 46 is multiplied by their difference, we first calculate the sum: 59 + 46 = 105. Next, we find the difference: 59 - 46 = 13. Finally, we multiply the sum by the difference: 105 * 13 = 1365. Therefore, the product is 1365.
The product of the square of 1/2 and the sum of 13 and 19 is 169/4.
Next time use a calculator.15 * 13 = 195
To find the LCM, you multiply the numbers together and then divide by the HCF. In this case, we don't know the numbers, but we have the HCF (13) and we have the product of the numbers (1690). Thus all you do is divide 1690 by 13 to get: 1690/13 = 130 And thus the LCM of two numbers whose hcf is 13 and product is 1690 is 130.
Use the array suffix operator ([]), or use a pointer offset from the start of the array, such that an offset of 1 is equivalent to the size of an array element (all elements in an array must be of equal size). The latter method is what actually goes on behind the scenes when using the array suffix operator, but the former is generally easier to use.
13 and 14. Also negative 13 and negative 14.
-13*-14 = 182
The product of 13 and 3 is calculated by multiplying the two numbers together. In this case, 13 multiplied by 3 equals 39. Multiplication is a mathematical operation that combines two numbers to find their total value. In this instance, 13 groups of 3 equals 39.
2*2*2*2*13 = 208 or 24*13 = 208
11 and 13