13 and 14. Also negative 13 and negative 14.
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∙ 2010-01-08 16:00:1213 x 14 = 182
One way to find out is write a formula. Let N and N+1 be the two integers, then N(N+1) = 182 N^2 + N - 182 = 0 This is a quadratic equation. If the factors are not obvious, (N -13)(N + 14) , then use the quadratic formula to find N. The factors tell you there are two possible solutions for N; 13 and -14. Now add 1 to these to get the two consecutive integers. 13 & 14 will work and -14 & -13 will work.
182.
you put 182 over 100 182/100
1x182=182
-13*-14 = 182
13 x 14 = 182
13 and 14
The integers are 13 and 14.
The numbers are 13 and 14.
13 x 14 = 182
There is no set of four consecutive numbers with a product of 182. There is a set of four consecutive numbers with a sumof 182: 9, 20, 21 and 22.
There are two consecutive even integers: 90 and 92.
The integers are 180, 182 and 184.
13 x14 = 182
One way to find out is write a formula. Let N and N+1 be the two integers, then N(N+1) = 182 N^2 + N - 182 = 0 This is a quadratic equation. If the factors are not obvious, (N -13)(N + 14) , then use the quadratic formula to find N. The factors tell you there are two possible solutions for N; 13 and -14. Now add 1 to these to get the two consecutive integers. 13 & 14 will work and -14 & -13 will work.
2 and 91