To work out the mass of wire you need to know its volume. The wire is circular so that volume would just be the cross sectional area (pi * r^2) multiplied by the length of wire. Lets call the length L.
The equation is then volume = pi * radius^2 * L.
To get the mass of the wire we now multiply this equation by denstiy of the wire; that is how much the wire weighs per volume. Assuming the wire is steel this would be around 800Kg/m^3. So what you want to do is work out the volume as above, then multiply by 800, making sure that your units are consistant....ie lenght and radius in metres.
how to calculate the weight of 30x30 squre tube 2mm thick
To calculate the Safe Working Load (SWL) for spreader support wires, first determine the breaking strength of the wire or cable being used. Then, apply a safety factor, typically ranging from 5 to 10, depending on the application and regulations. The SWL is calculated by dividing the breaking strength by the safety factor. For example, if the breaking strength is 1000 kg and the safety factor is 5, the SWL would be 200 kg.
Weight per metre length= 0.559 kg
A penstock, with an internal diameter of 1.3 m, supplies water at a head equivalent to 127.6 kg/cm2. There is a possibility of 23per cent increase in the pressure due to transient conditions. The design stress and the efficiency of the joint may be assumed to be 1023 kg/cm2 and 35 per cent respectively.Calculate the approximate wall thickness of the penstock required
Think of electricity as water in a pipe. The larger the pipe the more water can flow thru. That is current = volume = amperage = amount of heat. Voltage can be compared to pressure in a pipe. That is drive/force. Most welding machines allow you to control the amperage but not the voltage.
1.2mm mig weighs 0.0087kg/meter therefore 1.724km per 15kg spool
wire weight = material_density * 3.14159 * (0.5 * cable_diameter)² * cable_length example for copper with 152 meter length: ---------------------------------------- material_density for copper = 8960 kg/m³ cable_diameter=0.006 meter cable_length=152 meter weight of wire = 8960 kg/m³ * 3.14159 * (0.5 * 0.006)² * 152 = 38.51 kg lenght and diameter must be calculated in "meters" density must be in "kg/m³"
The number of 6013 welding rods in 1 kg depends on the length and diameter of the rods. Typically, a standard 6013 rod is 3.2 mm in diameter and about 350 mm long, weighing approximately 0.4 kg each. Therefore, you can expect to have around 2 to 2.5 rods per kilogram, depending on specific dimensions and manufacturing variations.
Mercury: diameter 4880 km mass 3.302e+23 kg Venus: diameter 12104 km mass 4.856e+24 kg Earth: diameter 12756 km mass 5.9742e+24 kg Mars: diameter 6796 km mass 6.419e+23 kg Jupiter: diameter 142984 km mass 1.899e+27 kg Saturn: diameter 120536 km mass 5.685e+26 kg Uranus: diameter 51118 km mass 8.683e+25 kg Neptune: diameter 49528 km mass 1.0243e+26 kg
The amount of weldable meters from a 15kg spool of FCAW 71T wire depends on several factors, including the wire diameter and the type of joint being welded. Generally, a rough estimate is that 1 kg of wire can weld approximately 1 to 1.5 meters, depending on the application. Therefore, a 15kg spool could yield around 15 to 22.5 meters of weld. For precise calculations, it's best to refer to specific welding parameters and joint designs.
To calculate the weight of a 12 mm diameter, 10 m long concrete reinforcement bar (rebar), you can use the formula: weight (kg) = (length in meters × diameter in mm × 0.00617). For a 12 mm diameter bar, the weight would be approximately 0.74 kg/m. Therefore, for a 10 m length, the total weight would be about 7.4 kg.
The weight of 2mm galvanized iron (GI) wire can be estimated using the formula for the weight of steel wire, which is approximately 0.56 kg per meter for 2mm diameter. Therefore, one meter of 2mm GI wire would weigh around 0.56 kg, though this can vary slightly based on the specific density and coating of the wire.
Flexible steel wire rope (FSWR) To calculate the SWL in kilograms of FSWR square the rope diameter (D) in millimetres (mm) and multiply by 8. Formula: SWL (kg) = D2(mm) x 8 For example: Rope dia (D) = 12 mm SWL(kg) =D2 (mm)x8 = D (mm) x D (mm) x 8 = 12 x 12 x 8 = 1152 kg SWL (t) = 1.15 tonnes The above equation can be reversed to calculate the diameter (D) in millimetres of FSWR needed to lift a given load. To do this, divide the load (L) in kilograms by 8 and find the square root of the result. Formula: D(mm) = √L(kg) 8 For example: Load = 1152 kg D (mm) = √1152 ÷ 8 = √144 = 12 (mm) Therefore a FSWR sling of at least 12 mm in diameter is required to lift a 1152 kg load for a straight lift.
18144 kg to CKG
A men's discus weighs 2 kg and has a diameter of 220mm.
It is twice its radius
Mercury: diameter 4880 km mass 3.302e+23 kg Venus: diameter 12104 km mass 4.856e+24 kg Earth: diameter 12756 km mass 5.9742e+24 kg Mars: diameter 6796 km mass 6.419e+23 kg Jupiter: diameter 142984 km mass 1.899e+27 kg Saturn: diameter 120536 km mass 5.685e+26 kg Uranus: diameter 51118 km mass 8.683e+25 kg Neptune: diameter 49528 km mass 1.0243e+26 kg