The volume of a sphere refers to the number of cubic units that will exactly fill a sphere. Its metric unit is the liter.
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You can also use cubic linear dimensions (cubic metre and its divisions), depending really on what is the most sensible for the application.
The bourdon tube is a curved oval cross-sectional tube. The tendency of a fluid under pressure to try to shape its container, the tube, into a spherical shape causes the tube to elongate, moving the dial mechanism to a position indicating the application of pressure. The greater the pressure applied the greater the movement of the tube.
A Rotameter is a device that measures the flow rate of liquid or gas in a closed tube. It is occasionally misspelled as "rotometer." It belongs to a class of meters called variable area meters, which measure flow rate by allowing the cross-sectional area the fluid travels through to vary, causing some measurable effect.
Draft tube has following purpose :- 1. It makes possible the installation of the turbine above the tail race level without the loss of head. 2. the velocity of water at the runner outlet is very high. By employing a draft tube of increasing cross sectional area, the discharge takes place at a much lower velocity and thus, a part of the kinetic energy that was going as a waste is recovered as a gain in the pressure head, and this increases the efficiency of the turbine. 3.The draft tube prevents the splashing of water coming out of the runner and guides the water to the tail race.
Measure the outer diameter of the tube and its' length. Calculate each tube volume and multiply by number of tubes. For those who want to calculate the inside liquid capacity of the shell side, it is advise to include the baffle volume with the tube bundle volume.
by u tube manometer
To calculate the cross sectional area of a rectangular tube, multiply the widths of two adjacent sides of the tube.
The answer depends on the cross-sectional area as well as the length.
The cross-sectional area of a tube is equal to the area of the outer circle minus the area of the bore, so using the formula for area of a circle, we can do the following. A = pi*(42/2)2-pi*(26/2)2 = 272 pi, A = 854.513 mm2
If the flow tube radius on the left is increased, the flow rate will increase because a larger cross-sectional area allows for more fluid to pass through. Conversely, if the flow tube radius on the left is decreased, the flow rate will decrease as the smaller cross-sectional area restricts the flow of fluid. The flow rate is directly proportional to the radius of the flow tube.
7.6 ml
The height of the column in a mercury barometer is determined by pressure, not force. Fluid pressures depend on density and depth-pressure at the bottom of a wide column of mercury is no different than the pressure at the bottom of a narrow column of mercury of the same depth. The weight of fluid per area of contact is the same for each. Likewise with the surrounding air. Therefore barometers made with wide barometer tubes show the same height as barometers with narrow tubes of mercury.
By area do you mean cross sectional area of a stream tube? Bernoulli's principle only compares pressure and velocity and it covers all fluids. In the case of an ideal gas (constant density) decreasing the cross sectional area of a stream tube lets say; will not affect the pressure. But given any fluid volume..going from point a to point b if velocity decreases, particles in the fluid want to move outward. just remember any fluid must do two things move and apply pressure.
Generally, the heat transfer area of reference is considered to be the outside surface area of the tube. Therefore, figure the outside diameter of the tube to get the heat transfer area.
Cross sectional area= 144x1.5=216mm2 Weight = 216x0.00271=0.58536kg/m for 1.5mm thick section
take the difference of areas of the outer and inner diametersA = pi x (3.42 squared - 2.4 squared) divided by 4pi = 3.14A = 4.66 sq cm3.77 cm
Resistance in a wire varies directly as its length and inversely as the cross-sectional area of the wire. If the cross-sectional area is big, more electricity and hence more energy can pass through it. As an analogy consider two metal tubes each exactly 1 foot long. One of them has a cross-sectional area of 1 square inch. The other has a cross-sectional area of 6 square inches. Imagine also a big water tank with unlimited water in it. Now imagine the two one foot metal tubes are inserted into the side of the water tank at the same height . You will observe that water gushes out more from the 6 square inch tube compared to the water coming out of the 1 square inch tube. Electric currents through conductors behave in a similar fashion.
Imagine a glass tube with equal cross-section of 1 square cm and of length 100 cm. Fill the tube with the liquid of density 'd' to the 75cm mark.The pressure at the bottom of each tube is the force exerted per unit area by the column of liquid in the tube. We have conveniently selected tubes with 1 sq cm (unit area in CGS system) cross sectional areas. So the weight of the column in the tube would be the pressure. Hence the pressure in the tube would be1) Weight of the 75cm liquid column = 75 x d x g = 75dg dynesThe presuure depends on the density in a linear proportion.Read more: How_does_liquid_pressure_vary_with_density_of_liquid