If I am correctly understanding the question. You are simply looking for the area of a circle or pi * R^2 or pi/4 * D^2. ------------------------------------ The formula above is correct for the planar cross section area through the center of the sphere, where the constant pi = 3.14159.... and R is the radius of the sphere, and D is the diameter. If the plane you are interested in does not go through the center of the sphere, it is not correct. To get the area though a plane that does not go through the center, you need to know the offset distance of the plane from the center of the sphere. Calling this distance d, the area is A = pi * (R^2 - d^2) [Positive values only. If the answer comes out negative, the offset distance is greater than the radius of the sphere, so the plane does not intersect the sphere] This can be derrived from a simple 2-D diagram.
The bourdon tube is a curved oval cross-sectional tube. The tendency of a fluid under pressure to try to shape its container, the tube, into a spherical shape causes the tube to elongate, moving the dial mechanism to a position indicating the application of pressure. The greater the pressure applied the greater the movement of the tube.
A Rotameter is a device that measures the flow rate of liquid or gas in a closed tube. It is occasionally misspelled as "rotometer." It belongs to a class of meters called variable area meters, which measure flow rate by allowing the cross-sectional area the fluid travels through to vary, causing some measurable effect.
Draft tube has following purpose :- 1. It makes possible the installation of the turbine above the tail race level without the loss of head. 2. the velocity of water at the runner outlet is very high. By employing a draft tube of increasing cross sectional area, the discharge takes place at a much lower velocity and thus, a part of the kinetic energy that was going as a waste is recovered as a gain in the pressure head, and this increases the efficiency of the turbine. 3.The draft tube prevents the splashing of water coming out of the runner and guides the water to the tail race.
Measure the outer diameter of the tube and its' length. Calculate each tube volume and multiply by number of tubes. For those who want to calculate the inside liquid capacity of the shell side, it is advise to include the baffle volume with the tube bundle volume.
by u tube manometer
To calculate the cross sectional area of a rectangular tube, multiply the widths of two adjacent sides of the tube.
The answer depends on the cross-sectional area as well as the length.
The cross-sectional area of a tube is equal to the area of the outer circle minus the area of the bore, so using the formula for area of a circle, we can do the following. A = pi*(42/2)2-pi*(26/2)2 = 272 pi, A = 854.513 mm2
If the flow tube radius on the left is increased, the flow rate will increase because a larger cross-sectional area allows for more fluid to pass through. Conversely, if the flow tube radius on the left is decreased, the flow rate will decrease as the smaller cross-sectional area restricts the flow of fluid. The flow rate is directly proportional to the radius of the flow tube.
7.6 ml
The height of the mercury column in a barometer is determined by the pressure of the atmosphere pushing down on the mercury in the dish, rather than the cross-sectional area of the barometer tube. This height is a result of balancing the weight of the mercury with the atmospheric pressure. Changing the cross-sectional area would only affect the amount of mercury needed to create this balance, not the height of the column.
By area do you mean cross sectional area of a stream tube? Bernoulli's principle only compares pressure and velocity and it covers all fluids. In the case of an ideal gas (constant density) decreasing the cross sectional area of a stream tube lets say; will not affect the pressure. But given any fluid volume..going from point a to point b if velocity decreases, particles in the fluid want to move outward. just remember any fluid must do two things move and apply pressure.
Generally, the heat transfer area of reference is considered to be the outside surface area of the tube. Therefore, figure the outside diameter of the tube to get the heat transfer area.
Cross sectional area= 144x1.5=216mm2 Weight = 216x0.00271=0.58536kg/m for 1.5mm thick section
take the difference of areas of the outer and inner diametersA = pi x (3.42 squared - 2.4 squared) divided by 4pi = 3.14A = 4.66 sq cm3.77 cm
Thick wires conduct more energy because they have lower resistance. Lower resistance means less energy is lost as heat while the electricity flows through the wire, allowing more energy to reach its intended destination. Thicker wires also have more surface area for current to flow through, further reducing resistance.
Imagine a glass tube with equal cross-section of 1 square cm and of length 100 cm. Fill the tube with the liquid of density 'd' to the 75cm mark.The pressure at the bottom of each tube is the force exerted per unit area by the column of liquid in the tube. We have conveniently selected tubes with 1 sq cm (unit area in CGS system) cross sectional areas. So the weight of the column in the tube would be the pressure. Hence the pressure in the tube would be1) Weight of the 75cm liquid column = 75 x d x g = 75dg dynesThe presuure depends on the density in a linear proportion.Read more: How_does_liquid_pressure_vary_with_density_of_liquid