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Sequentially divide it by two, rounding down each time and recording the remainder. Read that sequence of remainders backwards, and that is your binary value.

203 / 2 = 101 R 1

101 / 2 = 50 R 1

50 / 2 = 25 R 0

25 / 2 = 12 R 1

12 / 2 = 6 R 0

6 / 2 = 3 R 0

3 / 2 = 1 R 1

1 / 2 = 0 R 1

So 203 in decimal can be expressed as 11001011 in binary. Now we can confirm this:

1 * 128 + 1 * 64 + 0 * 32 + 0 * 16 + 1 * 8 + 0 * 4 + 1 * 2 + 1 * 1

= 128 + 64 + 8 + 2 + 1

= 203

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Q: How do you convert decimal number 203 to binary?
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