It's a simple example of addition.The solution looks like this:10 + 9 + 7 + 6 + 6 + 6 + 5 = 49
3 + 4 + 5 + 6 + 9 + 7 + 6 + 8 + 5 + 2 = 55
Well done to the student in question but what exactly is your question?
p + q + r = (2x - 9y) + (5y + 6 - 4x) + (3x + 3y - 5) = x - y + 1
46
(c - 2)(c - 3)
the Answer is 696969696969696969696969696
15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)
4c/15+5c/6 8c/30+25c/30 33c/30
C - 6C + 7 = -5C + 7
The value of c is 6
-5c-6=29 29 + 6= 35 -5c=35 c=7
-x2 + 2x + 48 = (-x - 6)(x - 8) = -(x + 6)(x - 8)
The expression cannot be factored.
The factors of 6 are 1, 2, 3, 6. For them to be common, they need to be compared to another set of factors.
6 is a factor
if you mean 6-5c=-29:c=7