c2 + 5c + 6 = (c + 2)*(c + 3)
Wiki User
∙ 2012-05-22 21:44:39It's a simple example of addition.The solution looks like this:10 + 9 + 7 + 6 + 6 + 6 + 5 = 49
3 + 4 + 5 + 6 + 9 + 7 + 6 + 8 + 5 + 2 = 55
14 plus 10 plus 7 plus 6 plus 5 plus 5 equals 47.
Well done to the student in question but what exactly is your question?
The next number is 20, because 5 plus 1 is 6 and 6 plus 2 is8 and 8 plus three is eleven and eleven plus four is fifteen etc.
(c - 2)(c - 3)
the Answer is 696969696969696969696969696
The common factor of 3n2+6 is 3.
15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)
4c/15+5c/6 8c/30+25c/30 33c/30
-5c-6=29 29 + 6= 35 -5c=35 c=7
The value of c is 6
C - 6C + 7 = -5C + 7
-x2 + 2x + 48 = (-x - 6)(x - 8) = -(x + 6)(x - 8)
The expression cannot be factored.
6 is a factor
if you mean 6-5c=-29:c=7