(5c - 2)(c +1)
4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)
15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)
12c + 2b
Group 5c-2c and 7d-3d and it comes to 3c+4d
c2+6c+9 = (c+3)(c+3)
2(5c + 2d)(5c + 2d)
(5c - 2)(c +1)
There is a formula for the "difference of squares." In this case, the answer is (5c - 14d)(5c + 14d)
4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)
15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)
9c is.
12c + 2b
The like terms are sums of b terms and c terms separately 5c+2c+3c+4b 5c +2c + 4b + 3c => 10c + 4b
the Answer is 696969696969696969696969696
7c+4
The GCF is 1.