How do you write logic for palindrome numbers?

Answer 1

#include <stdio.h> int main() { int n, n1, rev = 0, rem; printf("Enter any number: \n"); scanf("%d", &n); n1 = n; /* logic */ while (n > 0){ rem = n % 10; rev = rev * 10 + rem; n = n / 10; } if (n1 == rev){ printf("Given number is a palindromic number"); } else{ printf("Given number is not a palindromic number"); } return 0; }

Answer 2

1stly u hv to knw wat is palindrom no. ans is palindrom no. is the after doin reverse of any no. u ll get same no. called palindrom.

chart:

1. take input number

2.apply while loop(num!=0)

set condition in loop

rem=num%0;

rev=rev*10+rem;

num=num/10;

3.if(num==rev)

thn palindrom otherwise not.

so above is step and for flow chart take a box of while loop n one line coonect to condtion in the loop box and other for if condition box u ll get flow chart of it.

hope u ll got wat i said if NT reply me i ll make more understanding.