The rule of thumb for fusing the motor is 300% of the full load amps. To answer this question a voltage value for the motor is needed.
That would depend on the type of electricity used and the type of motor. The answer will be different for DC, single phase AC, two phase AC, and three phase.
There are many types of motors as well: split-phase, brush less, squirrel cage, synchronous, etc. Each one has different characteristics.
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The amperage draw at motor start up will be roughly 300% of the FLA (Full Load Amperage) of the nameplate rating.
if this motor is single phase ampere is 16.95 ampere .
if this motor isa 3 pH ampere is 7 ampere . ( at normal operation )
Smaller rating electrical motors usually takes 3 to 4 times the full load current at the time of starting for fraction of seconds.
To answer this question the voltage must be given. I = W/E. Amps = Watts / Voltage.
To answer this question the voltage of the motor must be given. The rule of thumb is 300% of the full load amperage.
To answer this question the voltage of the motor must be stated.
Depends on how big the motor is. A stronger motor will draw more amps then a weaker or less efficient motor. For example a wiper motor draws far less then a starter motor.
read the name plate on the motor
Then you are trying to get more HP out of the motor that it can supply. Back off on the load that the motor is driving or put a bigger motor onto the load.
Look at the motor nameplate and it shoud have the amp draw on it. If the nameplate is missing, then the amp draw depends on what type of motor it is. The basic calculation to get you in the ball park would be as follows: 1 HP = 0.75 KW 7.5 HP = 5.63 KW Assume the efficiency of the motor is 80%, then the power supplied will need to be 5.63/0.8 = 7.04 KW amp draw = 7040/220 = 32 amps <<>> For calculation purposes the electrical code book states that a 7.5 HP motor draws 40 amps.