import java.io.*;
class PrimeNumber
{
public static void main(String[] args) throws Exception
{
int i;
BufferedReader bf = new BufferedReader(
new InputStreamReader(System.in));
System.out.println("Enter number:");
int num = Integer.parseInt(bf.readLine());
System.out.println("Prime number: ");
for (i=1; i < num; i++ ){
int j;
for (j=2; j<i; j++){
int n = i%j;
if (n==0){
break;
}
}
if(i == j){
System.out.print(" "+i);
}
}
}
}
output:
Enter number:
50
Prime number:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47BUILD SUCCESSFUL (total time: 3 seconds)
In QBASIC, you can write a simple program to input the number 64751315 and sum its digits as follows: DIM sum AS INTEGER sum = 0 INPUT "Enter a number: "; number FOR i = 1 TO LEN(number) sum = sum + VAL(MID$(number, i, 1)) NEXT PRINT "The sum of the digits is "; sum This program prompts the user to input a number, iterates through each digit, converts it to an integer, and adds it to the total sum, which is then printed out.
Output a prompt.Either:Read from standard input (std::cin) to an integer.Or:Read a line from standard input (std::getline()) to a string.Create a string stream (std::stringstream) to read the string.Read from the string stream to an integer.For each integer from 2 to half the entered integer:If the entered integer is divisible by the current integer:The number is not prime.Exit the program.The number is prime.Exit the program.
No, but 2 and 3 are.No because integers are whole numbers
In a three digit integer number the tenthsdigit is always 0 as integer numbers are whole numbers and have no decimal part and tenths are decimal parts:tenths_digit_of_integer_number = 0I suspect you mean "How to find the tens digit of an integer number?"; this is the second from the right, so:tens_digit = (INT(number ÷ 10)) MOD 10For example, in C this would become: tens_digit = (number / 10) % 10;
In Visual Basic .NET, you can create a simple program to add two numbers by using input boxes or text fields to gather user input. For example, you would declare two variables to store the numbers, convert the input to numeric types, and then perform the addition. Finally, you can display the result using a message box or a label. Here's a basic example: Dim num1 As Integer = Convert.ToInt32(InputBox("Enter first number:")) Dim num2 As Integer = Convert.ToInt32(InputBox("Enter second number:")) Dim sum As Integer = num1 + num2 MessageBox.Show("The sum is: " & sum)
see the program
Real numbers consist of all numbers except complex numbers. Every integer is a natural number but every rational number is not a natural number as well as an integer. So, the answer to the question is integer.
A decimal number is not an integer. An integer is a number that is not a fraction, and decimal numbers are decimal fractions.
Integer are whole numbers. As 63.46 is not a whole number, it is not an integer.
In QBASIC, you can write a simple program to input the number 64751315 and sum its digits as follows: DIM sum AS INTEGER sum = 0 INPUT "Enter a number: "; number FOR i = 1 TO LEN(number) sum = sum + VAL(MID$(number, i, 1)) NEXT PRINT "The sum of the digits is "; sum This program prompts the user to input a number, iterates through each digit, converts it to an integer, and adds it to the total sum, which is then printed out.
Rational numbers are numbers that can be written as a fraction. Irrational Numbers cannot be expressed as a fraction. Any number that is a fraction is not an integer, but rational.
No. An integer is a kind of number - a whole number - but not all numbers are integers. For example, a half is a number but it is not an integer.
No because integers are whole numbers
There is no integer which is not a real number.
An integer is not always a whole number because whole numbers are numbers 0 and up. Integers are numbers above and below 0. (Including negatives.) So therefore, if an integer is a negative, it would not be a whole number. But a whole number is always an integer.
yes because its an integer and its a number
Output a prompt.Either:Read from standard input (std::cin) to an integer.Or:Read a line from standard input (std::getline()) to a string.Create a string stream (std::stringstream) to read the string.Read from the string stream to an integer.For each integer from 2 to half the entered integer:If the entered integer is divisible by the current integer:The number is not prime.Exit the program.The number is prime.Exit the program.