Sum of digits of a number equals to the given number?

Answer 1

(I'm assuming base 10 math) You could cheat. Convert the number to a string with no leading zeros. Capture the left most and right most characters of the string. Convert captured string variables back to integers. Add the integers. (Note: Consider a base string having a string length of 0 or 1.)

Answer 2

// returns the sum of the digits of num

int sumDigits(int num) {

int sum = 0;

int currentDigit;

// four step algorithm:

// step 1: loop until we have no digits left to process

while(num > 0) {

// step 2: find out the rightmost digit

currentDigit = num % 10;

// step 3: add the rightmost digit to our sum

sum += currentDigit;

// step 4: remove the rightmost digit from num

num /= 10;

}

return sum;

}

Answer 3

#include

#include

using namespace std;

int main()

{

int n,m,sum=0;

cout<<"Enter n:";

cin>>n;

m=n;

while(n>0)

{

sum+=n%10;

n=n/10;

}

if(sum==m)

cout<<"Equal :";

else

cout<<"Not equal";

return 0;

}

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Answer 4

int n; // we want to find the sum of digits of n

int sum = 0;

while(n != 0 ) {

sum += n % 10;

n /= 10;

}

Answer 5

for (sum=0; n!=0;) sum+=n%10, n /= 10;