81
They are the same because they are both multiplication. They also can be the same if the two digit number times by the one digit number equals a three digit number. They are different because the 3 digits number will obviously produce a higher product.
Any two digit number in which: (a) the units digit is not 0, and (b) the two digits are different will form a new 2-digit number when the digits are interchanged.
The greatest two-digit composite number would be 99, since 99 can be divided by 11, 9, and 3. I you look around this number, you will see why: 98 is also a composite number, but it is smaller than 99. 100 is also a composite number, but it has three digits. 97 has two digits, but it is a prime number. On the other hand, 99 divided by 11= 9, 99 divided by 9= 11, and 99 divided by 3=33.
Not necessarily. Consider 444. The digits are not different. The first and second digits are not multiples of 3 The first digit is not greater than the second digit. In spite of all that, 444 is a 3-digit number
By the sum of its digits: 10. By each of its individual digits: 11.
Its Impossible. I say this because anything that is three digits divided by a one digit number that equals 8 is not possible. For example the higher 1 digit number that you can multiply by eight is nine so I did 8x9 and got 72 which is not a three digit number. The lowest three digit number that 8 goes into is 104 which is 13x8 and 13 is not a one digit number. Therefore the problem is impossible. :)
81
Any number that ends in 0 or 5 and has three digits.
2178
2 or 3 digits.
Take the question apart, one step at a time. The remainder, when the number is divided by 5, is 4. That means that the ones digit is either 4 or 9. However, you know that both digits are odd, which means it has to be 9. The sum of the digits is 10, so the tens digit has to be 1. Your number is 19.
0.0588
yes
Let's assume there are 5 total digits, although that would have been handy information to include. All we can deduce from the available information is 4 of the digits. 318_2 There are ten possible digits for the 4th number, leaving 10 possible numbers.
This is a question of permutations; the answer is equal to the factorial of 5 (number of digits) divided by the factorial of 3 (number used in each selection), written 5! / 3!. This equals 120 / 6, or 20 ways.
Since there are only five different digits, a 6-digit number can only be generated if a digit can be repeated. If digits can be repeated, the smallest 6-digit number is 111111.