If the amount of water leaving the tube each second is equivalent to the volume of the tube, then the net velocity will equal the length of the tube per second. Therefore the net velocity for any length or flow rate will equal: v=l2πr2/(dV/dt) Where v is the the net velocity, r is the radius, l is the tube length, V is the volume and t is time. i.e. dV/dt is the flow rate
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You need to know two important dimensions of the pipe: the length and the inside radius (1/2 the inside diameter).
From there, you plug the dimensions in to this formula: radius2 x Pi (3.1416) x length. It is easiest if you ensure the dimensions are in the same format, such as feet or inches. Here is a sample:
The volume of a 50-foot long pipe with an inside diameter of three feet (1.5' foot radius) would be calculated as such:
Now there is the important final step of converting cubic feet to gallons of liquid. There are about 7.48 gallons in one cubic foot.
Since we know there are 1,413.72 cubic feet in the sample pipe above, we simply multiply 1,413.72 x 7.48 resulting in a maximum fluid volume of about 10,574.6256 gallons of water.
First, get the volume of water in the pipe. Assume the pipe is completely full, and the formula for the Volume =
Volume = Pi (3.14159) X Radius of pipe 2 X Length of pipe
Then convert Volume to Weight.
So, for 10 feet of 4" Inside Diameter pipe:
Radius = 1/2 * Diameter = 1/2 * 4 inch = 2 inch
Length = 120 inches
Volume = 3.14159 X 22 X 120 = 1,508 cubic inches
1 cubic inch of water = 0.036127 pounds
So: 1508 cubic inches * 0.036127 pounds per cubic inch = 54 pounds.
To calculate the pressure loss due to friction for pipe flow (I think this is what you're asking) use theDarcy-Weisbachequation. The friction factor for this equation can be calculated using the Swamee-Jain equation.
Alternatively, the simpler Hazen--Williams equation can be used. It is less accurate, but has the advantage of being easier to use. The equation can also be used to calculate flow in terms of head loss.
Wikipedia has detailed explanations for each of the above equations.
what is weight of 60 dia ms pipe
the weight of the water above. water in a 1" pipe 100' tall is 43 psi @ base of pipe. water in a 50' tank 100' tall is 43 psi @ base of tank. h x .434 = psi
A water pipe.
water pipe
Static pressure is .434 X height Example 10 ft x .434 4.34 PSI to prove take 2.31 PSI x 4.34 To find FORCE to need to calculate the diameter of the piping and the height and then the weight of the water inside the pipe