Ohm's Law Voltage = Current x Resistance
To calculate X/R, you must know what X and R are, then simply divide. The transformer test report should provide this information, and if not, there are ANSII standard values that can be used as estimates. The X value, or the % impedance are usually given explicitly in the test report (sometimes both, but not always). The R value may be given as load loss at the base MVA rating. To find % R, take the load loss (in watts or kilowatts), and divide by the base MVA. The % impedance is = %R + j%X, so you may need to do some (vector) math to get %X if not explicitly given.
#include<stdio.h> #include<conio.h> void main() { int x[10],r; for(int i=1;i<=5;i++) { printf("enter the number"); scanf("%d",&x[i]); } r=x[5]-x[1]; printf("%d",r); getch(); }
........V I = ------ ........R I = Ohm's Law V = Voltage R = Resistance (Ignore the dots they stop V and R from moving to the left!)
the equation that convert from cartesian to polar coordinates and vice versa r = sqrt (x*x+y*y); phi = atan2 (y, x); x = r*cos (phi); y = r*sin (phi);
Known Ratio gives: X/Y = R Known Area gives: X*Y = A R and A are known. Two equations. Two unknowns. X = R*Y R*Y*Y = A Y^2 = A/R Y = SQRT(A/R) X = R*SQRT(A/R)
What is the ratio of two odd functions? Ans: f, g are odd func on the same domain D. Let r = f / g, assuming g non zero everywhere on D. r(-x) = f(-x) / g(-x) = -f(x) / [-g)(x)] = f(x) / g(x) = r(x), and so r is an even function.
If you are given a ratio, r , then r = x/y ( If the ratio is given as x : y, or x to y think of it as x/y . Also remember the r% means r/100 if the ratio is given as a percentage. ) Therefore by basic algebra, x = ry and y = x/r . So you find either number from the other, given the ration. Example The ratio of boys to girls in a physics class is 8 to 2. There are 4 girls. How many boys are in the class? b/g = 8/2 so b/4 = 8/2 and b = 4(8/2) = 16 boys in the class.
Surface area of sphere is 4 x pi x r x r Volume of sphere is (4/3) x pi x r x r x r Hence ((4/3) x pi x r x r x r) / (4 x pi x r x r) = 1/2 ((4/3) x r) / (4) = 1/2 (1/3) x r = 1/2 r = 1 and 1/2
The ratio is given as the sphere volume divided by the volume of the cone. The volume of a sphere that satisfies these conditions is 4/3 x pi x r cubed, and the volume for the cone is 2/3 x pi x r cubed, where r is the radius and pi is equal to 3.14. Dividing these two volumes, you find the resulting ratio is 2.
Volume of a sphere of radius r: V = 4pi/3 x r3 If the ratio of the radii of two spheres is 23,then the ratio of their volumes will be 233 = 1,2167
Sum of 10 terms is n(r10-1)/(r-1) where n = 1st term. Sum of 20 is n(r20-1)/(r-1) so ratio is (r20-1)/(r10-1). Let r10 be called x. So the ratio is (x2-1)/(x-1) which is just x+1, so x=243. The common ratio is therefore the 10th root of this. Which is square root of 3.
Probably... What ratio? X/R? X0/X1? X0/R0? Xd /Xd''? etc.
All you need to do is use a Punnet Square for this. You will get the following genotypical and phenotyical ratio from this cross: RrBb x RRbb = RRBb RrBb RRbb Rrbb In terms of phenotypical ratios, 50% of the offspring have a chance of showing R and B, and the other half have the chance of showing R and b.
Two quantities are in a Golden Ratio if the ratio of the bigger quantity to the smaller quantity is the same as the ratio of the sum of the two quantities to the bigger quantity. In algebraic form, if the two quantities are x and y, and x is the bigger of the two, then they are in the Golden Ratio if x/y = (x+y)/x and that ratio is the Golden Ratio. which equals (1 + √5)/2.
let edge of the cube be {x} radius of the sphere inside the cube= x/2 volume of the cube=x^3 volume the sphere=4pi/3*r^3 =4/3*22/7*r^3/8 ratio of the volume=x^3/11x^3/21 =21/11 ans.= 21:11
Ohm's Law Voltage = Current x Resistance