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either to friction (heat, sound, light) or to internal mechanical changes

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Power doesn't 'go' anywhere! Power is simply a 'rate': the rate at which the machine is doing work. If the machine isn't doing work by supplying a mechanical load, then it's output power is zero. However, energy still has to be provided to overcome the losses due to heat transfer from the machine, friction, windage, etc. The rate at which this energy is supplied to the motor is the power of the machine off load.

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Q: Where does the input power go when the mechanical output power is zero?
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What gate the output will be low for any case when one or more input are zero?

An inverter has a high output when the input is low, and a low output when the input is high.


What is the relationship between energy input energy output and energy losses whenever transfer of energy takes place?

Energy input = energy output + losses. Both energy output and losses are usually positive (they might also be zero in some specific cases), meaning that (usually) each of them individually is less than the energy input.


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It depends on the shunt feedback resistor on the op-amp, for example with a 10k feedback resistor connecting the output to the inverting input, 1 mA input current gives 10 volts signal output. The input terminal stays near zero voltage because of the high open-loop gain of the op-amp, so the inverting input is termed a 'virtual earth'.


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A negative clamper circuit is considered. It shifts original input signal in a downward direction.While positive input is applied, diode is forward biased. The output voltage is Vo which is equal barrier potential of the diode. The capacitor is charged to V-Vo.When negative input cycle, diode does not conduct because it is reverse biased and the capacitor can not discharge very much because time constant (RC) choosen is high. Now output is sum of input voltage and capacitor voltage and it is equal to -(2V - Vo). Now peak to peak output voltage is difference of output voltages when positive and negative half cycles and it is equal to V-(-(2V - Vo)) or 2V.In negative clamper, input signal is pushed downward and positive peak of the output signal coincides with zero level.In positive clamper circuit, unlike in negative clamper circuit, diode is connected reversely.There is no change in connection of capacitor. But resistor is connected after diode. Positive clamping circuit shifts a input signal in upward direction. The output of this circuit shows that negative peak of signal coincides with zero level.


If the input resistor is 3k ohms and the feedback resistor is 33k ohms in an inverting amplifier what is the voltage gain?

If the input resistor is 3k ohms and the feedback resistor is 33k ohms in an inverting amplifier the voltage gain is -11, the ratio of 33 over 3. Consider this... The negative input terminal is a virtual ground, assuming that the positive terminal is tied to ground (usually) through a resistor. That means you have a simple voltage divider between output and input, and the output will be whatever it takes to get the common point (the negative input) to be zero. From there, its all just Ohm's law.

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