Start at 2 and double every turn
0+2=2.....2+4=6....6+8=14....14+16=30..and..30+32=62
The answer is 62!
In a Fibonacci sequence, sum of two successive terms gives the third term.... here is the Fibonacci sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144........ General formula to generate a Fibonacci sequence is """Fn= Fn-1 + Fn-2""" To check whether a number is Fibonacci or not follow the following steps: 1) Get the number as input from user. 2) Fix the first two numbers of sequence as 0 and 1. 3) put a sentinel loop with upper limit being the input number. 4)in the body of loop generate the next number in sequence in each iteration and continue swapping the values as follows: a=0 b=1 next=a+b while (next< input) a=b b=next next=a+b wend 5) lastly when program exits the loop compare the last number of sequence with the input number if they are equal then number is Fibonacci otherwise not. otherwise the last term of sequence will be less than the input number.
Store the numbers in a suitable container such as an array. Assume the first number is the smallest and assign its value to a local variable. Traverse the remainder of the sequence, comparing each element's value to the stored value. If an element has a lower value, assign its value to the local variable. When the sequence is fully traversed, the local variable will hold the value of the smallest value in the sequence. Return that value.
To print lucky numbers in java, you must give the following program: class example { static public void main(String[] args) { System.out.println("Lucky number is your favourite number which is your DOB"); } }
I don't program in just C (I use C++) so you may have to change some of the code:int main(){int n;int last = 1;int slast = 0;int numbers[n];numbers[0] = 1;for(int i = 1; i < n; i++){numbers[i] = last + slast;slast = last;last = numbers[i];}return 0;}int n needs to be set to however many Fibonacci numbers you want to make.int last is the last number in the sequence (so far)int slast is the second last number in the sequence (so far)int numbers[n] is the int array which holds your numbersint i is the count for the loop, it is set to 1 because before the loop, I set numbers[0] to 1
Handsome numbers are the numbers in which the sum of all the left side numbers is equal to the last number for example 123 - 1+2=3 its a handsome number
10
10
5
8
62
17?
6
The numbers are increasing by 1,4,9,16,25,36.... which are square numbers so the next increase is 49. Making the next number in the sequence 141
21. This is the Fibonacci series.
From the pattern (n + 4, n + 2, n + ?) I would say the next following number is 20 (n + 1).
A single number, such as 3773949588525642992, does not constitute a sequence.
34. Each number is the sum of the two preceding numbers. This is called the Fibonacci Sequence.